Answer:
9 bottles of soda and 7 bottles of juice
Step-by-step explanation:
Let x be the number of bottles of soda purchased and y be the number of bottles of juice purchased.
1. Gabriel purchased 2 more bottles of soda than bottles of juice, then

2. Each bottle of soda has 35 grams of sugar, then there are 35x g of sugar in x bottles of soda.
Each bottle of juice has 10 grams of sugar, then there are 10y g of sugar in y bottles of juice.
In total, there are 35x+10y g of sugar.
All bottles collectively contain 385 grams of sugar, thus

3. Solve the system of two equations:

Substitute the first equation into the second equation:

Answer:
-3-5i
Step-by-step explanation:
Answer:
r = (ab)/(a+b)
Step-by-step explanation:
Consider the attached sketch. The diagram shows base b at the bottom and base a at the top. The height of the trapezoid must be twice the radius. The point where the slant side of the trapezoid is tangent to the inscribed circle divides that slant side into two parts: lengths (a-r) and (b-r). The sum of these lengths is the length of the slant side, which is the hypotenuse of a right triangle with one leg equal to 2r and the other leg equal to (b-a).
Using the Pythagorean theorem, we can write the relation ...
((a-r) +(b-r))^2 = (2r)^2 +(b -a)^2
a^2 +2ab +b^2 -4r(a+b) +4r^2 = 4r^2 +b^2 -2ab +a^2
-4r(a+b) = -4ab . . . . . . . . subtract common terms from both sides, also -2ab
r = ab/(a+b) . . . . . . . . . divide by the coefficient of r
The radius of the inscribed circle in a right trapezoid is r = ab/(a+b).
_____
The graph in the second attachment shows a trapezoid with the radius calculated as above.
Answer:
7 (7.07106781187)
Step-by-step explanation:
All you have to do is find the diameter of the rectangle from two farthest corners. To do this, use the Pythagorean Theorem
(5^2) + (5^2) = c^2
25 + 25 = c^2
50 = c^2
7 ≈ c
Answer:
A) 159.135 = X
B) 2,531.25 = X
C) 6,187.5 = X
D) 831,947.46 = X
Step-by-step explanation:
The following investments are required to be calculated:
A) $ 150 at 3% interest for 2 years
B) $ 750.00 at 1/2% interest for 3 years
C) $ 2,250.00 at 1 3/4% interest for 1 year
D) $ 2,550.00 at 3 1/4 interest for 4 years
Therefore, the following calculations must be performed:
A)
150 x (1 + 0.03) ^ 2 = X
150 x 1.03 ^ 2 = X
159.135 = X
B)
750 x (1 + 0.5) ^ 3 = X
750 x 1.5 ^ 3 = X
2,531.25 = X
C)
2,250 x (1 + 1.75) = X
2,250 x 2.75 = X
6,187.5 = X
D)
2,550 x (1 + 3.25) ^ 4 = X
2,550 x 4.25 ^ 4 = X
831,947.46 = X