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garri49 [273]
3 years ago
6

Find (g o f)(-1). *

Mathematics
1 answer:
klio [65]3 years ago
6 0

Answer:

D  -9

Step-by-step explanation:

(g o f)(-1) = g(f(-1))

f(-1) = f(-1)  =  (-1)^{2}  +  2(-1) - 3\\=  1 - 2 - 3\\=  -4

g(-4) = -4 - 5 = -9

So, (g o f)(-1) = -9

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Question Progress<br> Homework Progress<br> 4/<br> Work out the size of angle x.<br> 105<br> 140
agasfer [191]

Answer:

Step-by-step explanation:

Sum of angles of a triangle = 180

x + (180 - 105) + (180 -140) = 180

x + 75 + 40 = 180

x = 180 -75 - 40

x = 65

5 0
3 years ago
ra\\For spirit week at a local high school, students were encouraged to wear their school colors of green and white. 1,200 stude
s344n2d4d5 [400]

Answer:

<em>20%</em>

Step-by-step explanation:

<em>First, add 1,200, and 300. That gives you 1,500. You want to find how much percent of 1,500 equals 300, and that is 20%.</em>

4 0
2 years ago
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I need help with math!!! time is running out!!! will mark brainliest!!!
marin [14]

These are the elements of the matrix

Elements of the first row are h11 h12 h13, of the second row h21 h22 h23.

Than we can conclude that element h23 worth 75.

Good luck!!!

3 0
3 years ago
Read 2 more answers
At a farm, the average number of chickens, ducks, rabbits and sheep is 315 per type of animal. The average number of chickens, d
Greeley [361]

The average number of chickens, ducks, rabbits and sheep = 315 per type of animal.

The average number of chickens, ducks and rabbits = 320 per type of animal.

The number of sheep is 60 more than the number of rabbits.

Let us assume number of rabbits = x.

Number of sheep is 60 more than number of rabbits, that is = x+60.

There are half as many ducks as there are rabbits.

Therefore, number of ducks = x/2.

Let us assume number of chickens = y.

Adding  number of chickens, number of rabbits, number of sheep and number of ducks and dividing by 4 (because those are four types of animal).

\frac{y+x+x+60+x/2}{4}  = 315

Multiplying both sides by 4, we get

y+x+x+60+x/2 = 1260

Subtracting 60 from both sides

y+x+x+60-60+x/2 = 1260-60

y+x+x+x/2 = 1200.

Combining like terms .

y + 5x/2 = 1200

Multiplying both sides by 2, we get

<em>2y +5x = 2400  ------------equation (1)</em>

Adding  number of chickens, number of rabbits and number of ducks and dividing by 3 (because those are three types of animal).

\frac{y+x+60+x/2}{3}  = 320

Multiplying both sides by 3, we get

y+x+60+x/2 = 960

Subtracting 60 from both sides

y+ x+x/2 = 900

Combining like terms .

y+ 3x/2 = 900

Multiplying both sides by 2, we get

<em>2y+3x = 1800 --------------------equation (2)</em>

Multiplying first equation by 3 and second equation by -5, we get

(2y +5x = 2400 ) * 3   => 6y +15x = 7200

(2y+3x = 1800) *-5      =>

Adding

6y +15x = 7200

-10x + -15x = -9000.

_________________

-4y = -1800.

Dividing both sides by -4, we get

y=450.

<h3>Therefore, number of chickens are  450 there at the farm.</h3>


7 0
3 years ago
2.
Gekata [30.6K]

Answer: the system has no solution.

Step-by-step explanation:

\displaystyle\\

\left \{ {{x^2y=16\ \ \ \ \ (1)} \atop {x^2+4y+16=0\ \ \ \ \ (2)}} \right. .\\

Multiply\  both\  sides\  of\  the\  equation\ (2)\   by\  y\  (y\neq 0):\\

x^2y+4y^2+16y=0\\

We\  substitute\  equation\  (1)\  into\  equation\  (2):\\

16+4y^2+16y=0\\

4y^2+16y+16=0\\

4*(y^2+4y+4)=0\\

4*(y^2+2*y*2+2^2)=0\\

4*(y+2)^2=0\\

Divide\  both\  sides\  of\  the \ equation\  by\  4:\\

(y+2)^2=0\\

(y+2)*(y+2)=0\\

So,\ y+2=0\\

y=-2.\\

\displaystyle\\We\  substitute\  the\  value\  of\  y\  into\  equation\  (1):\\x^2*(-2)=16\\Divide\  both\  sides\  of\  the \ equation\  by\  -2:\\x^2=-8\\x^2\geq 0\\ Hence,\ the\ system\ has\ no\ solution.

7 0
1 year ago
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