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3 years ago

Find the product. Simplify your answer.

Mathematics

2 answers:

statuscvo [17]3 years ago

7 0

Answer:

1/5

Step-by-step explanation:

Factor x² - 5x - 6

x² - 5x - 6 = (x + 1)(x - 6)

$\frac{x-6}{(x+1)(x-6)}$

Cancel the common factor.

$\frac{1}{x+1}$

$\frac{1}{x+1}$ · $\frac{x+1}{5}$

$\frac{1*(x+1)}{5*(x+1)}$

Cancel the common factor.

1/5

tangare [24]3 years ago

3 0

Answer:

1/5

Step-by-step explanation:

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What is nuclear waste?whats the answer frnds

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3 years ago

A farmer has 20 acres to plant in wheat and barley. He has to plant at least 15 acres. Wheat costs $200 per acre to plant and ba

maria [59]

Answer:

16 acres of barley only (no acres of wheat)

Step-by-step explanation:

A graph shows cost of planting puts an upper limit on planted area. The lower limit is provided by the requirement to plant at least 15 acres. The vertices of the feasible solution region are ...

(wheat acres, barley acres) = {(0, 15), (0, 16), (3, 12)}

The profit associated with these scenarios will be ...

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To maximize profit, the farmer should plant 16 acres of barley.

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3 years ago

Which of the following has the greatest value <br>A)3³<br>B)5²<br>C)1¹⁰<br>D)2⁵

Alecsey [184]

Answer:

A - Highest is 27

Step-by-step explanation:

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3 years ago

Read 2 more answers

Given f(x)=5-3x, if f(x)=-19, find x

Dafna1 [17]

X would equal 8

Step-by-step explanation:

5-3(8) = -19

5 multiplied by negative 3 times 8 equals negative 19

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3 years ago

This extreme value problem has a solution with both a maximum value and a minimum value. use lagrange multipliers to find the ex

noname [10]

$L(x,y,z,\lambda)=10x+10y+2z+\lambda(5x^2+5y^2+2z^2-42)$

$L_x=10+10\lambda x=0\implies1+\lambda x=0$

$L_y=10+10\lambda y=0\implies1+\lambda y=0$

$L_z=2+4\lambda z=0\implies1+2\lambda z=0$

$L_\lambda=5x^2+5y^2+2z^2-42=0$

$\begin{cases}L_x=0\\L_y=0\\L_z=0\end{cases}\implies1+\lambda x=1+\lambda y=1+2\lambda z=0\implies x=y=2z$

$5x^2+5y^2+2z^2=5(2z)^2+5(2z)^2+2z^2=42z^2=42\implies z^2=1$

$z^2=1\implies z=\pm1\implies x=y=\pm2$

There are two critical points, at which we have

$f\left(2,2,1\right)=42\text{ (a maximum value)}$

$f\left(-2,-2,-1\right)=-42\text{ (a minimum value)}$

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3 years ago