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Yuri [45]
3 years ago
9

Find the time it takes for $9,200 to double when invested at an annual interest rate of 10%, compoun

Mathematics
1 answer:
STatiana [176]3 years ago
3 0

Answer:

years = natural log (total / principal) / rate

years = natural log (18,400 / 9,200) / 10

years = natural log (2) / 10

years = 0.69314718056 / 10

years = 6.9314718056

and this would be the time for ANY amount of money to double.

Step-by-step explanation:

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Finished goods inventory is $197,000. If overhead applied to these goods is $72,000, and the overhead rate is 150% of direct lab
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Step-by-step explanation:

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5 0
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Consider the parent graph f(x) = x2 . Then, g(x) is a translation according the rule: y = (x + 3)2 + 4. Find the graph g(x).
krok68 [10]
For this case we have the following parent function:
 f (x) = x ^ 2
 We apply the following function transformation:
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 Suppose that h> 0
 To graph y = f (x + h), move the graph of h units to the left.
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 Suppose that k> 0
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3 years ago
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