3 years ago

Find the time it takes for $9,200 to double when invested at an annual interest rate of 10%, compoun

Mathematics

1 answer:

STatiana [176]3 years ago

3 0

Answer:

years = natural log (total / principal) / rate

years = natural log (18,400 / 9,200) / 10

years = natural log (2) / 10

years = 0.69314718056 / 10

years = 6.9314718056

and this would be the time for ANY amount of money to double.

Step-by-step explanation:

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