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3 years ago

The following graph describes function 1 and the equation below it describes function 2:

1 answer:

8 0

Function 1:
f(x) = -x² + 8(x-15)f(x) = -x² + 8x - 120
Function 2:
f(x) = -x² + 4x+1
Taking derivative will find the highest point of the parabola, since the slope of the parabola at its maximum is 0, and the derivative will allow us to find that.
Function 1 derivative: -2x + 8 ⇒ -2x + 8 = 0 ⇒ - 2x = -8 ⇒ x = -8/-2 = 4

Function 2 derivative: -2x+4 ⇒ -2x + 4 = 0 ⇒ -2x = -4 ⇒ x = -4/-2 ⇒ x= 2
Function 1: f(x) = -x² + 8x - 120 ; x = 4
f(4) = -4² + 8(4) - 120 = 16 + 32 - 120 = -72

Function 2: f(x) = -x² + 4x+1 ; x = 2
f(2) = -2² + 4(2) + 1 = 4 + 8 + 1 = 13

Function 2 has the larger maximum.

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Ayuda por fa con estos ejercicios por fa urgente

Anna71 [15]

Step-by-step explanation:

A ball is thrown straight up from a rooftop 320 feet high. The formula below describes the ball's height above the ground, h, in feet, t seconds after it was thrown. The ball misses the rooftop on its way down and eventually strikes the ground. How long will it take for the ball to hit the ground? Use this information to provide tick marks with appropriate numbers along the horizontal axis in the figure shown.

h=-16t^2+16t+32

4 0

3 years ago

Question

lora16 [44]

Answer:

909 times

Step-by-step explanation:

$500,000/550= 909

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2 years ago

What is the slope of the line that passes through the points (9, 1) and (10, -1)? Write your answer in simplest form.

Otrada [13]

We conclude that the slope of the linear equation that passes through the points (9, 1) and (10, -1) is -2.

<h3>How to get the slope of the line that passes through the points (9, 1) and (10, - 1)?</h3>

A linear equation has the general form:

y = a*x + b

Where a is the slope of the line, and b is the y-intercept.

There is a simple equation to get the slope of a point if we know two points. For a line that passes through ( a, b) and (c, d), the equation for the slope is:

a = (d - b)/(c - a)

In this case we know that our line passes through (9, 1) and (10, -1), then using the above equation, we can see that the slope is:

a = (-1 - 1)/(10 - 9) = -2

We conclude that the slope of the linear equation that passes through the points (9, 1) and (10, -1) is -2.

If you want to learn more about linear equations:

brainly.com/question/1884491

#SPJ1

7 0

2 years ago

A company makes a cone-shaped container with a height of 15 in. The area of its base is about 78.8in.2 Approximately what is the

MakcuM [25]

Answer:

Approximately the volume of cone-shaped container is 393 in³.

Step-by-step explanation:

Given:

A company makes a cone-shaped container with a height of 15 in.

The area of its base is about 78.8 in².

Now, to get the cone-shaped container volume.

So, we find the radius first by using formula:

Let the radius be $r.$

(Using the value π = 3.14)

$A_{B}=78.8\ in^2.$

$A_{B}=\pi r^2$

$78.8=3.14\times r^2$

Dividing both sides by 3.14 we get:

$25.09=r^2$

Using square root on both sides we get:

$5.00=r$

$r=5\ in.$

Thus, the radius ( $r$ ) = 5 in.

The height ( $h$ ) = 15 in.

Now, to get the volume of the cone-shaped container we put formula:

$Volume=\pi r^2\frac{h}{3}$

$Volume=3.14\times 5^2\times \frac{15}{3} \\\\Volume=3.14\times 25\times 5\\\\Volume=392.50\ in^3.$

Therefore, approximately the volume of the cone-shaped container is 393 in³.

7 0

3 years ago

Please help thank you!

kirill [66]

Question 1:

Look at the image.

First, we graph the points on a grid.

Then, we find the perpendicular bisectors and find where they intersect.

They intersect on the circumcenter of the triangle.

The circumcenter is (5,3)

Question 2:

The answer is III only because the perpendicular bisector for the longest side will always have to point outside the triangle in order to intersect with the other two perpendicular bisectors.

Question 3:

The answer is a perpendicular bisector because it is a perpendicular line that bisects a side of the triangles, which is the exact definition of a perpendicular bisector.

Have an awesome day! :)

3 0

3 years ago