In proving that C is the midpoint of AB, we see truly that C has Symmetric property.
<h3>What is the proof about?</h3>
Note that:
AB = 12
AC = 6.
BC = AB - AC
= 12 - 6
=6
So, AC, BC= 6
Since C is in the middle, one can say that C is the midpoint of AB.
Note that the use of segment addition property shows: AC + CB = AB = 12
Since it has Symmetric property, AC = 6 and Subtraction property shows that CB = 6
Therefore, AC = CB and thus In proving that C is the midpoint of AB, we see truly that C has Symmetric property.
See full question below
Given: AB = 12 AC = 6 Prove: C is the midpoint of AB. A line has points A, C, B. Proof: We are given that AB = 12 and AC = 6. Applying the segment addition property, we get AC + CB = AB. Applying the substitution property, we get 6 + CB = 12. The subtraction property can be used to find CB = 6. The symmetric property shows that 6 = AC. Since CB = 6 and 6 = AC, AC = CB by the property. So, AC ≅ CB by the definition of congruent segments. Finally, C is the midpoint of AB because it divides AB into two congruent segments. Answer choices: Congruence Symmetric Reflexive Transitive
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Answer:
C .10
Step-by-step explanation:
Answer:
The segment is 6 units long.
Step-by-step explanation:
The points (–2, 4) and (–2, –2) are vertices of a heptagon. We have to explain how to find the length of the segment formed by these endpoints.
If two points at the ends of a straight line PQ are P(
) and Q(
), then the length of the segment PQ will be given by the formula
Now, in our case the two points are (-2,4) and (-2,-2) and the length of the segment will be
units. (Answer)
14^(7x) = 17^(-8-x)
Take the log of both sides:
7x*log 14 = -(8+x)*log 17, or 7x^log 14 = -8*log 17 - x*log 17.
Grouping the x terms, we get x(7*log 14 + log 17)= -8*log 17
Then:
-8*log 17
x= -------------------------- (answer)
7*log 14 + log 17
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Solving this equation
<h2>-7.4 + E = 9.11</h2><h2>E = 16.51</h2>
