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tino4ka555 [31]
3 years ago
15

a random sample of seventh graders shows the numbers of minutes they spend on personal hygiene each morning

Mathematics
2 answers:
Gre4nikov [31]3 years ago
5 0

Answer:

Step-by-step explanation:

u expect us to know the questions

IRINA_888 [86]3 years ago
3 0

Can you post the rest of the question

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N = 9
g100num [7]

Answer:

The <em>p</em>-value is 0.809.

Step-by-step explanation:

In this case we need to perform a significance test for the standard deviation.

The hypothesis is defined as follows:

<em>H</em>₀: <em>σ</em>₀ = 4 vs. <em>Hₐ</em>: <em>σ</em>₀ ≤ 4

The information provided is:

<em>n</em> = 9

<em>s</em> = 3

Compute the Chi-square test statistic as follows:

\chi^{2}=\frac{(n-1)s^{2}}{\sigma_{0}^{2}}

     =\frac{(9-1)\cdot (3)^{2}}{(4)^{2}}\\\\=\frac{8\times 9}{16}\\\\=4.5

The test statistic value is 4.5.

The degrees of freedom is:

df = n - 1

   = 9 - 1

   = 8

Compute the <em>p</em>-value as follows:

p-value=P(\chi^{2}_{9}>4.5)=0.809

*Use a Chi-square table.

Thus, the <em>p</em>-value is 0.809.

7 0
3 years ago
3/4×-18=1/4×-4 help me slove
WINSTONCH [101]

3/4 x -18 = 1/4 x -4

subtract 1/4 x from each side

3/4 x -1/4 x -18 = 1/4 x- 1/4 x -4

2/4 x - 18 = -4

add 18 to each side

1/2 x -18 + 18 = -4 + 18

1/2 x =14

multiply by 2 on each side

2* 1/2 x = 14 * 2

x =28

3 0
3 years ago
Read 2 more answers
Fill the missing values in the ratio table
kramer

Answer:

A really out of focus picture, but I think this might be what you want.

Step-by-step explanation:

8 0
3 years ago
Write a two-column proof. Given: &lt;2 is congruent to &lt;5; Segment AB is congruent to Segment DE Prove: Segment BC is congrue
kotykmax [81]

Answer:

proof

Step-by-step explanation:

Statements

Reasons

<2 is congruent to <5; Segment AB is congruent to Segment DE

Given

<3≅<4

Vertical angle theorem

ΔCDB≅ΔCAE

AAS

Segment BC is congruent to Segment EC

CPCTC

5 0
3 years ago
Sammy Sales had the following receipts for his tree trimming business for the first six months of the year. What is the average
fredd [130]

average =  \frac{sum \:  \: of \:  \:all \:  \:  obeservations}{no. \:  \: of \: observaions}

=  \frac{1205 + 1450 + 1530 + 1655 + 1610 + 1710}{6}

=  \frac{9160}{6}

=  1526.66

___________________________________________

1526.66 is the average of his sales for this period.

6 0
3 years ago
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