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2 answers:
![\bf\huge x=2](https://tex.z-dn.net/?f=%5Cbf%5Chuge%20x%3D2%20)
Step-by-step explanation:
<h2>Given that :</h2>
<h2>to find :</h2>
<h2>explanation :</h2>
⟼ ![\sqrt{x+7} -1=x\\](https://tex.z-dn.net/?f=%5Csqrt%7Bx%2B7%7D%20-1%3Dx%5C%5C)
⟼ √x + 7 = x + 1
⟼ x + 7 = x² + 2x + 1
⟼ x + 7 - x² - 2x - 1 = 0
⟼ -x + 6 -x² = 0
⟼ x² + x - 6 = 0
⟼ (x-2) (x+3) = 0
⟼ x = 2 and x = -3
<h3>
When x = -3 the original equation √x+7-1 = x does not hold true. We will drop x = -3 from the solution set. </h3>
Therefore,
⟼ x = 2.
<h2>
verification :</h2>
⟼ let take x = 2
⟼ ![\sqrt{x+7} -1=x\\](https://tex.z-dn.net/?f=%5Csqrt%7Bx%2B7%7D%20-1%3Dx%5C%5C)
⟼ √2+7 - 1 = 2
⟼ √9 - 1 = 2
⟼ 3 - 1 = 2
⟼ 2 = 2
<h2>hence verified ☑️</h2>
Answer:
x = 2 and x = -3
Step-by-step explanation:
We need to find the value of x in the below expression.
![\sqrt{x+7} -1=x](https://tex.z-dn.net/?f=%5Csqrt%7Bx%2B7%7D%20-1%3Dx)
Adding 1 to both sides,
![\sqrt{x+7} -1+1=x+1\\\\\sqrt{x+7}=x+1](https://tex.z-dn.net/?f=%5Csqrt%7Bx%2B7%7D%20-1%2B1%3Dx%2B1%5C%5C%5C%5C%5Csqrt%7Bx%2B7%7D%3Dx%2B1)
Squaring both sides,
![x+7=(x+1)^2\\\\x+7=x^2+1+2x\\\\x^2+1+2x-x-7=0\\\\x^2+x-6=0\\\\x=2\ and\ -3](https://tex.z-dn.net/?f=x%2B7%3D%28x%2B1%29%5E2%5C%5C%5C%5Cx%2B7%3Dx%5E2%2B1%2B2x%5C%5C%5C%5Cx%5E2%2B1%2B2x-x-7%3D0%5C%5C%5C%5Cx%5E2%2Bx-6%3D0%5C%5C%5C%5Cx%3D2%5C%20and%5C%20-3)
Hence, this is the required solution.
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