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valentinak56 [21]
3 years ago
15

randall opened a savings account on june 1st and made the following deposits: $212.19, june 5th $29.03, june 12 $307.15, june 19

th $652.00 and june 30, $78.75. assuming he made no withdrawals, approximately how much did he have in the savings account at the end of the month of june?

Mathematics
2 answers:
o-na [289]3 years ago
7 0
The answer is $1,279.12
Vlad1618 [11]3 years ago
3 0
<h2>Answer:</h2>

The amount of money he have in the savings account at the end of the month of June is:

                           $ 1279.12

<h2>Step-by-step explanation:</h2>

It is given that:

Randall opened a savings account on June 1st and made the following deposits:

June 1st        $212.19

June 5th       $29.03

June 12th      $307.15

June 19th      $652.00

and June 30  $78.75.

Also, he made no withdrawals this means that the amount of money in the end month of June will be equal to the sum of all the money that was deposited in the account in different days of June.

Hence, the amount of money in the account will be:

212.19+29.03+307.15+652+78.75

= $ 1279.12

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Compound interest <br> Plz help!!!
liraira [26]

Answer:

a) A(t) = 17500(1.0053)^{12t}

b) The balance after 8 years will be of $29,069.

Step-by-step explanation:

Compound interest:

The compound interest formula is given by:

A(t) = P(1 + \frac{r}{n})^{nt}

Where A(t) is the amount of money after t years, P is the principal(the initial sum of money), r is the interest rate(as a decimal value), n is the number of times that interest is compounded per year and t is the time in years for which the money is invested or borrowed.

a)

Loan of $17,500 means that P = 17500

6.4% interest rate means that r = 0.064

Compounded monthly means that n = 12. So

A(t) = P(1 + \frac{r}{n})^{nt}

A(t) = 17500(1 + \frac{0.064}{12})^{12t}

A(t) = 17500(1.0053)^{12t}

b)

This is A(8). Then

A(8) = 17500(1.0053)^{12*8} = 29069

The balance after 8 years will be of $29,069.

8 0
3 years ago
20.   The sum of two consecutive even integers is 158. Find the least of the two integers. 
Mumz [18]

Answer:

78

Step-by-step explanation:

The tricky part of this is figuring out how to assign the unknowns.  We are told that we are working with two consecutive even integers.  Consecutive means "next to" or "in order" and sum means to add.  If we use 2 and 4 as examples of our 2 consecutive even integers and assign x to 2, then in order to get from 2 to 4 we have to add 2.  So the lesser of the 2 integers is x, and the next one in order will be x + 2.  (2 and 4 are just used as examples; they mean nothing to the solving of this particular problem.  You could pick any 2 even consecutive integers and find the same rule applies.  All we are doing here with the example numbers is finding a rule for our integers.)  Now we have the 2 expressions for the integers, we will add them together and set the sum equal to 158:

x + (x + 2) = 158

The parenthesis are unnecessary since we are adding, so when we combine like terms we get

2x + 2 = 158 and

2x = 156 and

x = 78

That means that the lesser of the 2 integers in 78, and the next one in order would be 80, and 78 + 80 = 158

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3 years ago
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