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valentinak56 [21]
3 years ago
15

randall opened a savings account on june 1st and made the following deposits: $212.19, june 5th $29.03, june 12 $307.15, june 19

th $652.00 and june 30, $78.75. assuming he made no withdrawals, approximately how much did he have in the savings account at the end of the month of june?

Mathematics
2 answers:
o-na [289]3 years ago
7 0
The answer is $1,279.12
Vlad1618 [11]3 years ago
3 0
<h2>Answer:</h2>

The amount of money he have in the savings account at the end of the month of June is:

                           $ 1279.12

<h2>Step-by-step explanation:</h2>

It is given that:

Randall opened a savings account on June 1st and made the following deposits:

June 1st        $212.19

June 5th       $29.03

June 12th      $307.15

June 19th      $652.00

and June 30  $78.75.

Also, he made no withdrawals this means that the amount of money in the end month of June will be equal to the sum of all the money that was deposited in the account in different days of June.

Hence, the amount of money in the account will be:

212.19+29.03+307.15+652+78.75

= $ 1279.12

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nika2105 [10]
Let's call the distance from the beach to the playground x.
Let's call the distance from the stand to the parking lot z.
Let's call the base of the biggest triangle in the picture (from the parking lot to the left) y.

Recall the pythagorean theorem: the sum of the squares of the legs of a right triangle is equal to the square of the hypotenuse.

There are three right triangles we can work with.

Triangle with sides 48, x and z. Here z is the hypotenuse so we get the equation x^{2} + 48^{2} = z^{2}

Triangle with sides 27, x and y. Here y is the hypotenuse so we get 27^{2} + x^{2} = y^{2}

Triangle with sides z, y and (48+27). Here (48+27) is the hypotenuse so we get y^{2} + z^{2} = (27+48)^{2}. That is, y^{2} + z^{2} = 5625

We have 3 equations and 3 unknowns (x, y and z). So let's take the last equation: y^{2} + z^{2} = 5625 and replace z^{2} and y^{2} using expressions that contain an expression in terms of x from the first two equations we came up with.

That gives us: 48^{2} + x^{2} + x^{2} + 27^{2} =5625 which we solve for x as follows:

2 x^{2} + 3033 =5625&#10;2x^{2}  =2592&#10; x^{2} =1296&#10;x=36

Now that we know x we can substitute 36 for x into the equation 48^{2} + x^{2} = z^{2} and solve for z as follows:
48^{2} + 36^{2} = z^{2} &#10;2304+1296=z^{2} &#10;3600=z^{2} &#10;z=60

This means that the distance from the beach to the parking lot is 36 m and the distance from the stand to the parking lot is 60 m.
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