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arsen [322]
3 years ago
10

Solve x(x−5)+4(x−5)=0, for x.

Mathematics
2 answers:
Anna11 [10]3 years ago
7 0

Answer:

Step-by-step explanation:

x(x-5)+4(x-5)=0

x^2-5x+4x-20=0

x^2-1x-20=0

x^2-1x=-20

x^2=20/-1

x^2=20

square root of x^2=x

x=20

kherson [118]3 years ago
6 0
Here is your answer. Good luck!

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Check the picture below.

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2 years ago
Y+4/12-y-1/12=y/2<br><br> Pls! on a time limit
icang [17]

Answer:

y= 1/2

Step-by-step explanation:

5 0
2 years ago
Read 2 more answers
Write the function f(x) = 3x2 - 6x + 5 in vertex
weeeeeb [17]
3(x-1)^2 +2
This is your answer in vertex form, your h and k values are the vertex. Solving the function by using b/2a, we get that h is 1. ( in the equation 3 is your a, 6 is b and 5 is c.). ( 6/2(3)) = 1. We can then plug in 1 as x into the original equation and get positive 2 ( 3(1)^2 -6(1) +5) = 3-6+5 = 2. This is your vertex. In the function, your a value will always stay the same as this is your shrink or stretch. In this case, a is 3 so it will go outside the parenthesis. Put that all together and you get the function above.
Hope this helps :)
7 0
2 years ago
A survey is being planned to determine the mean amount of time corporation executives watch television. a pilot survey indicated
Natali [406]
Missing question: How many executives should be surveyed?

Solution:
Mean = 13 hours
SD = 3 hours
Confidence level = 95%

Mean viewing time within a quarter of an hour = 0.25 = 1.96*3/sqrt (N)

Where N = Sample population

N = {(1.96*3)/0.25}^2 = 553.19 ≈ 554

Therefore, 554 executives should be surveyed to yield such results.
5 0
3 years ago
Let us suppose we have data on the absorbency of paper towels that were produced by two different manufacturing processes. From
maksim [4K]

Answer:

The 95% CI for the difference of means is:

-155.45 \leq \mu_1-\mu_2 \leq -44.55

Step-by-step explanation:

<em>The question is incomplete:</em>

<em>"Find a 95% confidence interval on the difference of the towels mean absorbency produced by the two processes. Assumed that the standard deviations are estimated from the data. Round to two decimals places."</em>

Process 1:

- Sample size: 10

- Mean: 200

- S.D.: 15

Process 2:

- Sample size:  4

- Mean: 300

- S.D.: 50

The difference of the sample means is:

M_d=M_1-M_2=200-300=-100

The standard deviation can be estimated as:

\sigma_d=\sqrt{\frac{\sigma_1^2}{n_1}+\frac{\sigma_2^2}{n_2}}\\\\\sigma_d=\sqrt{\frac{15^2}{10}+\frac{50^2}{4}} =\sqrt{22.5+625}=\sqrt{647.5}=25.45

The degrees of freedom are:

df=n_1+n_2-2=10+4-2=12

The t-value for a 95% confidence interval and 12 degrees of freedom is t=±2.179.

Then, the confidence interval can be written as:

M_d-t\cdot \sigma_d\leq \mu_1-\mu_2 \leq M_d+t\cdot \sigma_d\\\\-100-2.179*25.45\leq \mu_1-\mu_2 \leq -100+2.179*25.45\\\\-100-55.45 \leq \mu_1-\mu_2 \leq -100+55.45\\\\ -155.45 \leq \mu_1-\mu_2 \leq -44.55

8 0
3 years ago
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