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s344n2d4d5 [400]
3 years ago
5

Plz help me like plzzzzz

Mathematics
2 answers:
Bingel [31]3 years ago
6 0
Is there a picture of the ramp?
Jobisdone [24]3 years ago
4 0
The answer is (4,-6).... hope this helps :)))
You might be interested in
Proving the Converse of the Parallelogram Side Theorem
Brrunno [24]

Answer:

do it yourself

Step-by-step explanation:

6 0
2 years ago
The graphs of functions f(x) and g(x) = f(x) + k are shown below:
Nataly [62]
Here's the info for f(x):  We are going to find the slope of the line and then write the equation for the line using one of the given points.  The coordinate points we are given are (0, 0) and (2, 4).  Using the slope formula:
m= \frac{y_{2} - y_{1} }{ x_{2}- x_{1}  }
gives us a slope equation of:
m= \frac{4-0}{2-0} and the slope is 2.  Using the point (0, 0) to write the equation of the line for f(x) looks like this in the slope-intercept form of the equation:
y- y_{1} =m(x- x_{1}) where m is the sloppe of 2 that we found and y_{1}  and  x_{1}  are the coordinates of one of the points.  It doesn't matter which one you choose; you will get the same answer whether you use (0, 0) or (2, 4): y-0=2(x-0)   Distributing that 2 into the parenthesis and simplifying gives you the equation of y = 2x, or in our function notation, f(x) = 2x.  Since f(x) is the first part of g(x), so far for g(x) we have that g(x) = 2x + k.  Now we will do the same thing for g(x) that we did for f(x) as far as writing its equation down; we don't need to find the slope cuz the slope of g(x) is the function f(x).  The equation for g(x), using the point (0, 2) (again, you could have used either point; I just picked (0, 2) cuz the other one has a decimal in it!): y - 2 = 2(x - 0).  Distributing that 2 into the parenthesis gives you this: y - 2 = 2x - 0; y = 2x + 2.  So 2 is your k value!

7 0
3 years ago
Read 2 more answers
Please help if you want! :)
Korolek [52]

Answer:

3 dollars

Step-by-step explanation:

15 x .2

Because you convert the percentage to a decimal

3 0
2 years ago
What is the solution to 2logg(x)= logg8+logg(x-2)?<br> X=-4<br> O x=-2<br> O x=4<br> O X=8
solniwko [45]

Answer:

3x

Step-by-step explanation:

3 0
3 years ago
Integrate <img src="https://tex.z-dn.net/?f=e%5E%7B4x%7D%5Csqrt%7B1%2Be%5E%7B2x%7D%20%7D%20dx" id="TexFormula1" title="e^{4x}\sq
AnnyKZ [126]

Answer:

(\frac{(1+e^{2x}) ^{\frac{5}{2} } }{{5}} + \frac{(1+e^{2x} )^{\frac{3}{2} } }{{3}} )+C

Step-by-step explanation:

<u><em> Step(i):-</em></u>

Given that the function

                    f(x) = e^{4x} \sqrt{1+e^{2x} }

Now integrating on both sides, we get

                 \int\limits{f(x)} \, dx = \int\limits{e^{4x} \sqrt{1+e^{2x} } dx

                               =    \int\limits{e^{2x} e^{2x} \sqrt{1+e^{2x} } dx

                         

<u><em>Step(ii):-</em></u>

  Let  1 + e^{2x}  = t

           e^{2x}  = t -1  

          2e^{2x}dx = d t

          e^{2x}dx = \frac{1}{2} d t

                = \int\limits{( \sqrt{1+e^{2x} }) e^{2x} e^{2x} dx

                  = \int\limits {\sqrt{t}(t-1)\frac{1}{2} dt }

                 = \frac{1}{2} \int\limits {\sqrt{t} (t) -\sqrt{t} ) dt }

                = \frac{1}{2} \int\limits {(t^{\frac{1}{2}  } t^{1} +t^{\frac{1}{2} } ) } \, dx

                = \frac{1}{2} \int\limits {(t^{\frac{3}{2}  } +t^{\frac{1}{2} } ) } \, dx

               = \frac{1}{2} (\frac{t^{\frac{3}{2} +1} }{\frac{3}{2}+1 } + \frac{t^{\frac{1}{2} +1} }{\frac{1}{2}+1 } )+C

              =  \frac{1}{2} (\frac{t^{\frac{3}{2} +1} }{\frac{5}{2} } + \frac{t^{\frac{1}{2} +1} }{\frac{3}{2} } )+C

             = \frac{1}{2} (\frac{t^{\frac{5}{2} } }{\frac{5}{2} } + \frac{t^{\frac{3}{2} } }{\frac{3}{2} } )+C

            = (\frac{(1+e^{2x}) ^{\frac{5}{2} } }{{5}} + \frac{(1+e^{2x} )^{\frac{3}{2} } }{{3}} )+C

<u><em>Final answer:-</em></u>

= (\frac{(1+e^{2x}) ^{\frac{5}{2} } }{{5}} + \frac{(1+e^{2x} )^{\frac{3}{2} } }{{3}} )+C

             

3 0
3 years ago
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