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3 years ago

PLEASE HELP I GIVE BRAINLIEST

Mathematics

1 answer:

melamori03 [73]3 years ago

4 0

Here is my answer. I hope this is helpful.

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How many different combinations of “on” and “off” are possible with 8 “lightbulbs”?

viktelen [127]

How many different combinations of “on” and “off” are possible with 8 “light bulbs”?

Answer: The total number of combinations of "on" and "off" that are possible with 8 "light bulbs" is $2^{8}=256$

Therefore, 256 different combinations of “on” and “off” are possible with 8 “light bulbs”

5 0

3 years ago

Round your response to at least 3 Decimal Places Answer AB&C

Kaylis [27]

The probabilities can be calculated using an online calculator or tables, depending on which is more readily available.

QUESTION A

$P(Z>1.48)$

Using calculators, the probability will be:

$P(Z\gt1.48)=0.069$

QUESTION B

$P(Z\leq1.94)$

Using calculators, the probability will be:

$P(Z\leq1.94)=0.974$

QUESTION C

$P(-0.76Using calculators, the probability will be:[tex]P(-0.76\lt Z\lt2.05)=0.756$

4 0

1 year ago

Miguel is playing a game in which a box contains four chips with numbers written on them. Two of the chips have the number 1, on

creativ13 [48]

Answer:

The answer is " $\bold{-\frac{1}{2}}$ "

Step-by-step explanation:

Miguel's choose the best way to win the 2 dollars by pulling the two chips with the number 1. In total, there are four balls, so his probability of winning is:

$\to \frac{2}{4} \times \frac{1}{3}= \frac{1}{6}$

The chances of losing a dollar add up to that amount, so 5/6.

Price predicted = $\frac{1}{6} \times (2) + \frac{5}{6} \times (-1)$

$=\frac{1}{6} \times 2 + \frac{5}{6} \times -1\\\\=\frac{1}{3} - \frac{5}{6} \\\\=\frac{2-5}{6}\\\\=\frac{-3}{6}\\\\=- \frac{1}{2}\\$

The final answer is " $-\frac{1}{2}$ "

6 0

3 years ago

Find value of the expressions a =4, b=2 and c =3 then 2(a+3b)-(b+c)

Blizzard [7]

Answer:

2(a+3b)-(b+c)=

2(4+3(2))-(2+3)=

2(4+6)-(5)=

2(10)-5=

20-5=

Step-by-step explanation:

8 0

2 years ago

50 raised to the power of zero

Vikentia [17]

When any number/base is raised to the power of zero, it will always equal 1.

5 0

3 years ago