Answer:
50 is the initial value
Step-by-step explanation:
The equation is of the form
y = ab^x where a is the initial value and b is the growth/decay value
b>1 is growth and b<1 means decay
y = 50(1.6)^x
50 is the initial value and 1.6 means growth since it is greater than 1
1.6 -1 = .6 so it has a 60% growth rate
<span>Which of the following is the solution set of the equation
10(x^2+1/x^20)-63(x-1/x)=52=0
I think you type wrongly the equation:
It is : </span><span>10(x^2+1/x^2)-63(x-1/x)+52=0
We know: x</span>²+1/x²=(x-1/x)²+2, pose x-1/x=t and we have x²+1/x²=t²+2
So 10(t²+2)-63t+52=0
or 10t²-63t+72=0
we have t=(63+33):20= 24/5
and t=(63-33):20=3/2
+ If t=3/2 we have x-1/x=3/2 or 2x²-3x-2=0 and we have x=2, x=-1/2
+ Of t=24/5 we have x-1/x=24/5 or 5x²-24x-5=0 or x=5 and x=-1/5
And the answer: <span>c) (5,2,-1/5,-1/2)</span>
Answer:
14/9
Step-by-step explanation:
(1+1/3)^2−2/9
=(4/3)^2-2/9
=16/9-2/9
=14/9
Answer:you get 0.0347582854x ^127
Step-by-step explanation:
The energy is compared based on the information given below.
<h3>How to illustrate the energy?</h3>
Energy released by burning 1 kilogram of element A = EA = 5.1 * (10)8
Energy released by fission of hydrogen in 1 kilogram of element B = EB = 1.3 * (10)10
Therefore,
Ratio = EB / EA = 1.3 * (10)10 / 5.1 * (10)8 = 25
Thus, the fission of 1 kg of element B releases 25 times as much energy as burning 1 kilogram of element A.
Learn more about energy on:
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<u>The other part of the question:</u>
Energy released by burning 1 kilogram of element A = 5.1 times 10 Superscript 8
Energy released by the fission of hydrogen in 1 kilogram of element B = 1.3 times 10 Superscript 10