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Alenkinab [10]
3 years ago
15

Draw the graph of y=2x+1

Mathematics
2 answers:
Natali5045456 [20]3 years ago
8 0

Step-by-step explanation:

you need to need to draw a straight line where y=2

Leni [432]3 years ago
8 0
Since it’s linear, find 3 points
(1, 3), (2, 5), (0, 1)
Now plot the points and draw a line through them
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Can you please help me
svetlana [45]

Answer:

<em>∠TUV = 56°</em>

Step-by-step explanation:

<em>∠TUV = 1/2 ∠TWV</em>

<em>∠TUV = 112° ÷ 2 = 56°</em>

7 0
3 years ago
Read 2 more answers
What is the difference between dash and hyphen
UNO [17]
Hyphens and Dashes. A hyphen joins two or more words together while a dash separates words into parenthetical statements. The two are sometimes confused because they look so similar, but their usage is different. Hyphens are not separated by spaces, while a dash has a space on either side.
8 0
3 years ago
Evaluate the limit as h goes to 0 of (3+h)^4 -81/h
Montano1993 [528]

Answer:6

Step-by-step explanation:Take the derivative of the numerator and denominator, then evaluate the limit.

8 0
3 years ago
Ella plans to make treats for her class.
PSYCHO15rus [73]

Answer:

2/3 * 25/1  = 50 / 3 = 16 66/100 = 16 4/25

Step-by-step explanation:

6 0
3 years ago
An acute triangle has sides measuring 10 cm and 16 cm. The length of the third side is unknown.
saveliy_v [14]

Answer: Choice B

12.5 < x < 18.9

================================================

Explanation:

We have a triangle with these side lengths:

  • a = 10
  • b = 16
  • c = x = unknown

Let's assume that b = 16 is the largest side of this triangle.

By the converse of the pythagorean theorem, we need b^2 < a^2+c^2 to be true in order for an acute triangle to happen.

So,

b^2 < a^2 + c^2\\\\c^2 > b^2 - a^2\\\\c > \sqrt{b^2-a^2}\\\\x > \sqrt{16^2-10^2}\\\\x > \sqrt{156}\\\\x > 12.4899959967968 \ \text{(approximate)}\\\\x > 12.5

Now let's consider the possibility that the missing side x is actually the longest side.

Using the same theorem as before, we would say,

c^2 < a^2 + b^2\\\\c < \sqrt{a^2 + b^2}\\\\x < \sqrt{10^2 + 16^2}\\\\x < \sqrt{356}\\\\x < 18.8679622641132 \ \text{(approximate)}\\\\x < 18.9\\\\

We found that x > 12.5 and x < 18.9

This is the same as saying 12.5 < x and x < 18.9

Put together, they form the approximate answer of 12.5 < x < 18.9

6 0
3 years ago
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