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Margaret [11]
3 years ago
6

express the numbers eight, fifteen and seventeen in base 2. I have forgotten how to do the base 2 question.

Mathematics
1 answer:
saw5 [17]3 years ago
6 0
The quickest way for converting small numbers like this to binary would probably be to find the closest power of 2, then add/subtract intermediate powers of 2 as needed.

Converting 8 is immediate, since it's already a power of 2:

8=2^3\implies 8_{10}=1000_2

Converting 15 and 17 is also pretty easy if you're familiar with the rules of arithmetic in binary.

15=16-1=2^4-2^0\implies 15_{10}=16_{10}-1_{10}=10000_2-1_2=1111_2

17=16+1=2^4+2^0\implies 17_{10}=10000_2+1_2=10001_2
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The airplane Li’s family will be flying on can seat up to 149 passengers. If 96 passengers are currently on the plane, which ine
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For this case, the first thing you should do is define a variable.
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 Writing inequality we have:
 x + 96  \leq  149

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An inequality that can be used to determine how many more people can board is:
 
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3 0
3 years ago
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2 years ago
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What is the slope of this line?​
Mamont248 [21]

Answer:

y= 2x

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4 0
3 years ago
<img src="https://tex.z-dn.net/?f=tan20%2B4sin20%3D%5Csqrt%7B3%7D" id="TexFormula1" title="tan20+4sin20=\sqrt{3}" alt="tan20+4si
zepelin [54]

tan( 20 ) + 4 Sin( 20 ) =

( Sin( 20 ) / Cos( 20 ) ) + 4 Sin( 20 ) =

Sin( 20 ) + 4 Sin( 20 ).Cos( 20 ) / Cos( 20 ) =

Sin( 20 ) + 2 × 2 Sin(20).Cos(20)/ Cos(20) =

Sin( 20 ) + 2 × Sin( 40 ) / Cos( 20 ) =

Sin( 20 ) + 2Sin( 40 ) / Cos( 20 ) =

Sin( 20 ) + 2Cos( 50 ) / Cos ( 20 ) =

Sin( 20 ) + 2Cos( 20 + 30 ) / Cos( 20 ) =

________________________________

2 × Cos( 30 + 20 ) =

2 × [ Cos(30).Cos(20) - Sin(30).Sin(20) ] =

2 × [ √3/2 × Cos(20) - 1/2 × Sin(20) ] =

√3 Cos(20) - Sin(20)

_________________________________

Sin( 20 ) + 2Cos ( 20 + 30 ) / Cos( 20 ) =

Sin( 20 ) + √3 Cos(20) - Sin(20) / Cos(20) =

Sin(20) - Sin(20) + √3 Cos(20) / Cos(20) =

0 + √3 Cos(20) / Cos(20) =

√3 Cos(20) / Cos(20) =

Cos(20) simplifies from the numerator and denominator of fraction

√3 × 1 / 1 =

√3

And we're done ....

5 0
2 years ago
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