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Sergio039 [100]
3 years ago
14

Match these together

Mathematics
1 answer:
MrMuchimi3 years ago
6 0
1. C
2. A
3. B
3. D

Hope this helps
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If the diameter of a circle is 2.5 inches what is the circumference of the circle
disa [49]

Answer:

7.85 inches

Step-by-step explanation:

4 0
3 years ago
Write x2 − 6x + 7 = 0 in the form (x − a)2 = b, where a and b are integers.
Mariulka [41]
X² − 6x + 7 = 0

Let's complete the square [x²-6x+(??)²] -(??)² +7 = 0

As you noticed we have added the unknown square & also subtract the same so that not to change the equation

The question now is to calculate this square (??)²

We know that the middle term (6x) is twice the square root of the 1st times the square root of the 2nd, That is 6x=2x (multiply) √(??)²

6x = 2x?? & ??=6x/2x===> ?? =3 & (??)² =9

Hence plug (??)² into the equation above:

x² - 6x + 9 - 9 +7 =0

(x²-6x+9) -9 + 7 =0

(x-3)² -2 =0 ====> (x-3)² = 2 (that is B)
7 0
4 years ago
Read 2 more answers
Which edges are parallel
Lady_Fox [76]
The answers are "EN and ZW" and "CV and LR"

Parallel lines can be described as being like the two L's in parallel.  Because they are both going in the same directions and have the same slope,  they will never touch even if you extended them to infinity. 
6 0
3 years ago
The weight of adults Male beagles are normally distributed, with a mean of 25 pounds and a standard deviation of 4 pounds.
a_sh-v [17]

Answer:

There is a 95.6% chance that the weight will fall within this range.

Step-by-step explanation:

This is because the extremes that are given are roughly two standard deviations from the mean. To be outside of that, there is only 2.2% likelihood to be higher and another 2.2% to be lower. When we subtract these two from 100%, we get our probability.

100% - 2.2% - 2.2% = 95.6%

6 0
3 years ago
The table shows the results of a poll of 200 randomly selected juniors and seniors who were asked if they attended prom. Find th
Zielflug [23.3K]

Answer:

(a)\frac{7}{25}

(b)\frac{19}{116}

(c)\frac{28}{125}

Step-by-step explanation:

Number of juniors who attended prom,n(J)=28

Number of seniors who attended prom,n(S)=97

  • Total of those who attended prom=125

Number of juniors who did not attend prom,n(J')=56

Number of seniors who did not attend prom,n(S')=19

  • Total of those who attended prom=75
  • Total Number of students=200

(a) P (a junior who did not attend prom)

P(J')=\frac{56}{200}= \frac{7}{25}

(b)

P(Senior)=\frac{116}{200}

P ($did not attend prom$ | senior)=\frac{\text{P(seniors who did not attend prom)}}{P(Senior)} \\=\frac{19/200}{116/200} \\=\frac{19}{116}

(c)P (junior | attended prom)

P(Senior)=\frac{84}{200}

P (Junior|$ attended prom$)=\frac{\text{P(juniors who attended prom)}}{P(\text{those who attended prom)}} \\=\frac{28/200}{125/200} \\=\frac{28}{125}

3 0
3 years ago
Read 2 more answers
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