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klemol [59]
2 years ago
14

The problem is Question Divide.52÷(−45)

Mathematics
2 answers:
Artemon [7]2 years ago
6 0

Answer:

-1.555

Step-by-step explanation:

52/(-45)= -1.555555

Veronika [31]2 years ago
6 0

Answer:

well i just worked it out and got -1.155556...

Step-by-step explanation: Sorry if this wasn't very helpful, i really did try though have an amazing day :D

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Given two terms in artimetic sequence find the common difference, the 52 term, and the explicit formula. A15=139 and A30=259
quester [9]

139, 149, 159, 169, 179, 189, 199, 209, 219, 229, 239, 249, 259.


The common difference is 13.


Let n = 52


Let d = common difference


a_52 = 139 + (52 - 1)(13)


a_52 = 139 + (51)(13)


a_52 = 139 + 663


a_52 = 802




4 0
3 years ago
  2<br>x^-8x+12<br> --------------<br>   2<br>x^-36
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\frac{x { }^{2}  - 2x - 6x + 12}{ (x - 6)(x + 6)}  \\  \\  \frac{x(x - 2) - 6(x - 2)}{(x  - 6)(x + 6)}  \\  \\ \frac{(x - 2)(x - 6)}{(x - 6)(x + 6)}  \\  \\  \frac{x - 2}{x + 6}
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3 years ago
Round 4,279 to the nearest thousand
anygoal [31]

Answer:

it is 4,000

Step-by-step explanation:

since you are rounding it to the nearest thousand, you loo at the 4, and the 2, the 2 is blow five, so it doesn't change the thousands place, but everything else becomes a 0

4 0
3 years ago
Read 2 more answers
I don’t get it. <br> Use the net to find the lateral area of the prism.
sesenic [268]

the net is pretty much the net of a long box, kinda like the one in the example in the picture below.  Due to that, we can pretty much assume the two sides sticking up and down, are just two small 6x3 rectangles, namely, they have a height of 3, reason why we assume that, if that if we fold the other sides to make out the box, those two sides sticking out, must be 3m to neatly snugfit.


now, if we close the box as it stands, the sides(laterals) will be on the left-right sides two 3x15 rectangles, and on the front-back sides, two 6x15 rectangles.


we're excluding the top and bottom sides, because those are not "laterals", or sides of the box.


\bf \stackrel{\textit{two rectangles, left and right}}{2(3\cdot 15)}+\stackrel{\textit{two rectangles, front and back}}{2(6\cdot 15)}&#10;\\\\\\&#10;90+180\implies 270

6 0
3 years ago
The scale on a map is 2 centimeters= 50 kilometres.Two rivers on a map are located 9.3 centimeters apart.What is The actual dist
Yuki888 [10]

Answer:

The actual distance between the two rivers is <u>232.5 kilometers</u>.

Step-by-step explanation:

GIven:

The scale on a map is 2 centimeters= 50 kilometres.Two rivers on a map are located 9.3 centimeters apart.

Now, to find the actual distance between the two rivers.

Let the actual distance between the two rivers is x.

The two rivers on the map is located apart of 9.3 centimeters.

According to the scale on the map is 2 centimeters = 50 kilometers.

<em>So, 2 centimeters is equivalent to 50 kilometers.</em>

<em>Thus, 9.3 centimeters is equivalent to </em>x.<em />

Now, to solve by using cross multiplication method:

\frac{2}{50} =\frac{9.3}{x}

<em>By cross multiplying we get:</em>

<em />2x=465<em />

<em>Dividing both sides by 2 we get:</em>

x=232.5\ kilometers.

Therefore, the actual distance between the two rivers is 232.5 kilometers.

6 0
3 years ago
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