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3 years ago

Does anyone know the answer???

Mathematics

2 answers:

pogonyaev3 years ago

8 0

It is the second one on the imagine

larisa86 [58]3 years ago

5 0

Answer:

Step-by-step explanation:

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What is the exact area of a circle with a radius of six feet?

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The answer is about 113.1 feet squared

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3 years ago

Which of the following below is the equation of the quadratic function f(x) with x-intercepts of 0 and -3 for which f(-1)=-2. A.

Paladinen [302]

✿————✦————✿

Answer: D

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2 years ago

Please help!!!

eduard

Answer: b. The adjacent angles formed by two intersecting lines are supplementary.

Step-by-step explanation:

In the given picture , we can see that there are intersecting lines with adjacent angles which have shown.

If we add the adjacent angles for each pair of intersecting lines we get,

$135^{\circ}+45^{\circ}=180^{\circ}$

$130^{\circ}+50^{\circ}=180^{\circ}$

$160^{\circ}+20^{\circ}=180^{\circ}$

Therefore,b is the right option "The adjacent angles formed by two intersecting lines are supplementary."

Two Angles are supplementary when their sum is 180 degrees.

Two Angles are complementary when their sum is 90 degrees.
Vertical angles are always equal.

3 0

3 years ago

Read 2 more answers

How many primes are between 2^31 and 2^32? What is the approximate ratio of primes to

PIT_PIT [208]

Answer:

Step-by-step explanation:183

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3 years ago

Solve square root of x + square root of x+2 = 2

andrew-mc [135]

The value of x is $\frac{1}{4}$

Step-by-step explanation:

Given:

$\sqrt{x} + \sqrt{x + 2} = 2$

Rearranging the radical on left side,

$\sqrt{x + 2} = 2 - \sqrt{x}$

Power on both sides,

$(\sqrt{x + 2})^{2} = (2 - \sqrt{x})^{2}$

Simplifying the left,

$x + 2 = (2 - \sqrt{x} )^{2}$

For the RHS equation, use the property of (a-b)² = (a²-2ab+b²),

$= > x + 2 = {2}^{2} - (2 \times 2 \sqrt{x}) + ( \sqrt{x})^{2}$

Now calculating its powers,

$= > x + 2 = 4 - 4\sqrt{x} + x$

Now sending -4√x to the LHS (left side), its sign becomes plus (+),

$= > 4 \sqrt{x} = 4 + x - x - 2$

Now the +x and -x will be cancelled,

$= > 4 \sqrt{x} = 4 - 2$

$= > 4 \sqrt{x} = 2$

Bringing 4 to the right side, it becomes the denominator,

$= > \sqrt{x} = \frac{2}{4}$

$= > \sqrt{x} = \frac{1}{4}$

Now powering both sides,

$= > ( \sqrt{x})^{2} = ( \frac{1}{2})^{2}$

$= > x = \frac{1}{4}$

4 0

2 years ago