Firstly, we will draw
RL series circuit
ET = 120 V, R = 40 Ω, and XL = 30 Ω
Firstly, we will find current

now, we can plug values
and we get

now, we can find voltage across L

so, we get

now, we can find absolute value



...............Answer
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Answer:
x = 1.71
Step-by-step explanation:
![x^3-20=-15\\x^3=-15+20\\x^3=5\\\sqrt[3]{x^3} =\sqrt[3]{5} \\x=1.71](https://tex.z-dn.net/?f=x%5E3-20%3D-15%5C%5Cx%5E3%3D-15%2B20%5C%5Cx%5E3%3D5%5C%5C%5Csqrt%5B3%5D%7Bx%5E3%7D%20%3D%5Csqrt%5B3%5D%7B5%7D%20%5C%5Cx%3D1.71)