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2 years ago

Eight years ago mario was 25% younger than he is now how old is mario now

Mathematics

2 answers:

Luda [366]2 years ago

5 0

32
this is because 25% equals 1/4 so 8 times 4 is 32

egoroff_w [7]2 years ago

4 0

Answer:

32.

Step-by-step explanation:

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Hey guys,<br><br> Do you guys know the answer to this TTM problem?<br><br> Thank You!

tensa zangetsu [6.8K]

I think it is 2.5,2.5

4 0

3 years ago

Hailey is making 36 mini- pumpkin pies. Each pie takes 6 ounces of pumpkin. The cans of pumpkin are 2 pounds each. How many can

serious [3.7K]

1 pound = 16 ounces

6 ounces each pie

36 mini pies to make

36 × 6 = 216 ounces needed to make 36 mini pies

216 ÷ 16 = 13.5 pounds
if each can of pumpkin is 2 pounds,
13.5 ÷ 2 = 6.75 so that would be 7 cans of pumpkin

3 0

2 years ago

Given that Cosecant (t) = negative StartFraction 13 Over 5 EndFraction for Pi less-than t less-than StartFraction 3 pi Over 2 En

Sergio [31]

Answer:

$\bold{cot(t) =\dfrac{12}{5}}$

Step-by-step explanation:

Given that:

$Cosec (t) = -\frac{13}5$

for $\pi < t < \frac{3 \pi}2$

That means, angle $t$ is in the 3rd quadrant.

To find:

Value of cot(t)

Solution:

First of all, let us recall what trigonometric ratios are positive and what trigonometric ratios are negative in 3rd quadrant.

In 3rd quadrant, tangent and cotangent are positive.

All other trigonometric ratios are negative.

Let us have a look at the following identity:

$cosec^2\theta -cot^2\theta =1$

here, $\theta =t$

So, $cosec^2t-cot^2t=1$

$\Rightarrow (-\dfrac{13}{5})^2-cot^2t=1\\\Rightarrow (\dfrac{169}{25})-cot^2t=1\\\Rightarrow \dfrac{169}{25}-1=cot^2t\\\Rightarrow \dfrac{169-25}{25}=cot^2t\\\Rightarrow \dfrac{144}{25}=cot^2t\\\Rightarrow cot(t)=\pm\sqrt{\dfrac{144}{25}}\\\Rightarrow cot(t)=\pm\dfrac{12}{5}$

But, angle $t$ is in 3rd quadrant, so value of

$\bold{cot(t) =\dfrac{12}{5}}$

4 0

3 years ago

Normal Distribution. Cherry trees in a certain orchard have heights that are normally distributed with mu = 112 inches and sigma

Lubov Fominskaja [6]

Answer:

The probability that a randomly chosen tree is greater than 140 inches is 0.0228.

Step-by-step explanation:

Given : Cherry trees in a certain orchard have heights that are normally distributed with $\mu = 112$ inches and $\sigma = 14$ inches.

To find : What is the probability that a randomly chosen tree is greater than 140 inches?

Solution :

Mean - $\mu = 112$ inches

Standard deviation - $\sigma = 14$ inches

The z-score formula is given by, $Z=\frac{x-\mu}{\sigma}$

Now,

$P(X>140)=P(\frac{x-\mu}{\sigma}>\frac{140-\mu}{\sigma})$

$P(X>140)=P(Z>\frac{140-112}{14})$

$P(X>140)=P(Z>\frac{28}{14})$

$P(X>140)=P(Z>2)$

$P(X>140)=1-P(Z$

The Z-score value we get is from the Z-table,

$P(X>140)=1-0.9772$

$P(X>140)=0.0228$

Therefore, the probability that a randomly chosen tree is greater than 140 inches is 0.0228.

5 0

3 years ago

100 BRAINLY POINTS!!!

BARSIC [14]

Answer:

C) $y=-0.5x+8$

Step-by-step explanation:

Line of best fit (trendline) : a line through a scatter plot of data points that best expresses the relationship between those points.

All the given options for the line of best fit are linear equations.

Therefore, we can add the line of best fit to the graph (see attached), remembering to have roughly the same number of points above and below the line.

Linear equation: $y=mx+b$

(where $m$ is the slope and $b$ is the y-intercept)

From inspection of the line of best fit, we can see that the y-intercept (where x = 0) is approximately 8. So this suggests that options C or D are the solution.

We can also see that the slope (gradient) of the line of best fit is approximately -0.5 (as the rate of change (y/x) is -1 unit of y for every +2 units of x).

Therefore, C is the solution, and the closet approximation to the line of best fit is $y=-0.5x+8$

4 0

2 years ago