Alrighty
squaer base so length=width, nice
v=lwh
but in this case, l=w, so replace l with w
V=w²h
and volume is 32000
32000=w²h
the amount of materials is the surface area
note that there is no top
so
SA=LW+2H(L+W)
L=W so
SA=W²+2H(2W)
SA=W²+4HW
alrighty
we gots
SA=W²+4HW and
32000=W²H
we want to minimize the square foottage
get rid of one of the variables
32000=W²H
solve for H
32000/W²=H
subsitute
SA=W²+4WH
SA=W²+4W(32000/W²)
SA=W²+128000/W
take derivitive to find the minimum
dSA/dW=2W-128000/W²
where does it equal 0?
0=2W-1280000/W²
128000/W²=2W
128000=2W³
64000=W³
40=W
so sub back
32000/W²=H
32000/(40)²=H
32000/(1600)=H
20=H
the box is 20cm height and the width and length are 40cm
3x + 2y = 12
2y = -3x + 12
y = -1.5x + 6
P^-4 x -5p
In properties of exponents, if the exponent is negative then you move the variable with the negative exponent to the denominators place and it changes to positive and the numerator becomes 1.
p^-4=1/(p^4)
Also, if no exponent is present it is understood to be 1.
Keeping this in mind,
p^-4 x -5p
1/(p^4) x -5p^1 substituted p^-4 by 1/p^4 and added ^1 to -5p
-5p^1/p^4 multiplied-5p^1 to 1
-5/p^3 simplified
Convert the angles to degrees. Remember there are 2pi radians in a circle, and a circle has 360 degrees, so conversion factor is 180degrees/pi. Then you can easily approximate the reference angle. Remember you make the reference angle from the positive x-axis and the reference angle will be the angle between the terminal side and the nearest x-axis (either positive side or negative side of the x-axis).
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Answer:
to be honest idek
Step-by-step explanation:
