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Nimfa-mama [501]
3 years ago
13

7/8 divided by 6 help me NOW please

Mathematics
2 answers:
UNO [17]3 years ago
7 0

Answer:

0.14583333333

Step-by-step explanation:

0.14583333333

slava [35]3 years ago
4 0
I think is 0.14583 but I’m not sure
You might be interested in
How many 30 are there in 600
strojnjashka [21]
The question that is asked is pretty straight forward. Only thing that needs to be found is the number of 30 in the number 600. By dividing 600 by 30 we can arrive at the desired result.
Number of 30 in 600 = 600/30
                                 = 60/3
                                 = 20
So there are 20 number of 30s in the number 600. This method can be used to find answers to several other similar kind of questions like the number of 10s in 1000.Following the same procedure we get
Number of 10 in 1000 = 1000/10
                                   = 100
5 0
3 years ago
Read 2 more answers
How do you solve -(-7) ​
tresset_1 [31]
The answer to -(-7) is 7
7 0
3 years ago
Read 2 more answers
Please help this is due tomorrow.<br><br> 1/2 of 20?
Mars2501 [29]

1/2 of 20 is 20/2 which is 10.

All you really need to do here is to divide 20 by 2 to get 10.


6 0
3 years ago
Read 2 more answers
A hot air balloon is descending
Harlamova29_29 [7]

Answer:

54 3/4

Step-by-step explanation:

18*3=54

1/4*3=3/4

6 0
3 years ago
In the data set below, what is the interquartile range?<br> 7<br> 1<br> 5<br> 5<br> 9<br> Submit
Marizza181 [45]

Answer:

5

Step-by-step explanation:

The interquartile range is the difference between the upper quartile and the lower quartile.

First find the median.

The median is the middle value of the data set arranged in ascending order

1  5  5  7  9 ← data in ascending order

       ↑ median

The lower quartile is the middle value of the data to the left of the median. If there is not an exact middle then it the average of the values on either side of the middle.

1  5

 ↑ lower quartile = \frac{1+5}{2} = 3

The upper quartile is the middle value of the data to the right of the median.

7  9

 ↑ upper quartile = \frac{7+9}{2} = 8

Thus

interquartile range = 8 - 3 = 5

3 0
3 years ago
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