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lisov135 [29]
2 years ago
12

How is primary storage different from secondary storage? Select the TWO correct statements. The CPU can only read and write data

on secondary storage. Users can only read and write data on primary storage. The CPU can only read and write data on primary storage. Users can only read and write data on secondary storage.​
Computers and Technology
2 answers:
ELEN [110]2 years ago
3 0

Answer:

i don't know but you can get Socratic  it scan questions and tell answers

Explanation:

Fed [463]2 years ago
3 0

Answer:

The CPU can only read and write data on primary storage.

 Users can only read and write data on secondary storage

Explanation:

i got it correct

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The code:

filename = input("> ")

with open(filename, "r") as file:

   items = file.read()

   items = items.split("\n")

   for index, item in enumerate(items):

       items[index] = item.split("\t")

   for item in items:

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Explenation:

1. We make the user enter the file's path, in our case "food.txt". This does only work if the .txt file is in the <u>same</u> directory as our code.

2. We get the content of our .txt file with the "open" function. If we use the "open" function inside of a "with" statement we don't have to deal with closing the file after we opened it. The file will close as soon as we exit the statement. The argument "r" indicates that we only want to read the file, not do anything else with it.

3. However the variable "file" doesn't contain the <u>contents</u> of "food.txt", only the class object of our file (if you try "print(file)" you'll only get nonsense). We can simply get the content of the file by calling ".read()" after.

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6. Now we have a list of lists of strings. The only thing left to do is go through every item and print it if the item's third item is equal to "Available" (notice that this is case-sensative). And print out the result in the desired format.

The code works for me, please ask me if there is anything you don't understand (or if the code is incorrect). Happy to help :D

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