Answer:
<u>The answer is option C. 6a-7</u>
Step-by-step explanation:
Given that
5(3a-1)-2(3a-2)=3(a+2)+v
Solve for v
∴ v = 5(3a-1)-2(3a-2) - 3(a+2)
∴ v = 15a - 5 - 6a + 4 - 3a - 6
∴ v = 15a - 6a - 3a - 5 + 4 - 6
∴ v = 6a - 7
<u>So the answer is option C. 6a-7</u>
Answers:
- Exactly 25%
- median = 450
- Not enough info (see below)
- IQR = 24
- IQR = 192
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Explanations:
- By definition, the quartiles split the data into four equal parts. The first quartile (Q1) will have 25% of the data below it.
- The second quartile is the exact same value as the median. This is because the median splits the data into two equal halves, i.e. is at the midpoint.
- There's not enough info. We can determine that 25% of the company makes more than $60,000, but we don't know how many people total work at the company. This info is missing.
- Subtract the third and first quartiles (Q3 and Q1) to get the interquartile range (IQR). So IQR = Q3 - Q1 = 45-21 = 24
- Same idea as the previous problem. IQR = Q3 - Q1 = 316.5 - 124.5 = 192
Answer:
- 6 2/3 qt 80%
- 13 1/3 qt 20%
Step-by-step explanation:
It is often convenient to solve a mixture problem by letting a variable represent the quantity of the higher-concentration contributor to the mix.
__
We can let x represent the number of quarts of 80% solution needed. Then (20-x) is the number of quarts of 20% solution needed. The amount of salt in the final mix is ...
0.80x +0.20(20-x) = 0.40(20)
0.60x = 0.20(20) . . . . . . . . subtract 0.20(20) and simplify
x = 20/3 = 6 2/3 . . . . . . . . . divide by 0.60; quarts of 80% solution
(20 -x) = 13 1/3 . . . . . . . . . . amount of 20% solution needed
The teacher should mix 6 2/3 quarts of 80% solution with 13 1/3 quarts of 20% solution.
Answer:
<h2>10000000000000</h2>
Step-by-step explanation:
<h2>minions </h2>
Step-by-step explanation:
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