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tankabanditka [31]
3 years ago
14

A dress usually sells for $67.00. If the dress is 30% off, what is the total price of the dress (excluding tax)?

Mathematics
2 answers:
sladkih [1.3K]3 years ago
7 0
46.90 is the answer
sattari [20]3 years ago
4 0

First, turn 30% into a decimal

30% / 100 = 0.3

Second, multiply.

0.3 * 67 = $20.10 is the discount

Third, subtract.

67 - 20.1 = $46.90 is the total price of the dress.

Best of Luck!

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Can someone please help me out thankss
Tamiku [17]

Answer:

3x +5x =90 +30

8x =120

x =15

6 0
3 years ago
B) How many terms are there<br>S.a) Find the value of x:<br>3 15<br>5 2x<br>3<br>5​
Allisa [31]

Answer:

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Step-by-step explanation:

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4 0
3 years ago
In this exercise, we consider strings made from uppercase letters in the English alphabet and decimal digits.
Yuri [45]

Answer:

  • a) 26^2 36^8
  • b) 21\cdot10\cdot36^7
  • c) 5^3 31^7
  • d) 10\cdot 9\cdot 8 \cdot 7 \cdot 26^6

Step-by-step explanation:

We will use the product rule from combinatorics.

  • a) There are 26 letters in the English alphabet, so there are 26 possible choices for the first character and 26 possible choices for the last one. Each one of the remaining eight characters of the string has 36 choices (letters or digits). By the product rule, there are 26\cdot36\cdot 36\cdots 36\cdot 26=26^2 36^8 strings.
  • b) We have 5 possible choices for the first character, it must be some vowel a,e,i,o,u. The second character can be chosen in 21 ways, selecting some consonant. There are 10 possibilities for the last character because only of the digits are allowed. The other seven characters have no restrictions, so each one can be chosen in 36 ways. By the product rule there are 21\cdot 10\cdot 36^7 strings.    
  • c) The third character has 5 possibilities. Repetition of vowels is allowed, so the sixth and eighth characters have each one 5 possible choices. There are seven characters left. None of them are a vowel, but they are allowed to take any other letter or digit, so each one of them can be chosen in 36-5=31 ways. Therefore there are 5^3 31^7 strings.
  • d) Remember that the binomial coefficient \binom{n}{k} is the number of ways of choosing k elements from a set of n elements. In this case, to count all the possible strings, we first need to count in how many ways we can select the four positions that will have the digits. This can be done in \binom{10}{4} ways, since we are choosing four elements from the set of the ten positions of the string. Now, for the first position, we can choose any digit so it has 10 possibilities. The second position has 9 possibilities, because we can't repeat the digit used on the first position. Similarly, there are 8 choices for the third position and there are 7 choices for the fourth. Now, these are the only digits on the string, so the remaining 6 characters must be letters, then each one of them has 26 possibilities. By the product rule, there are 10\cdot 9\cdot 8 \cdot 7 \cdot 26^6 strings.
3 0
4 years ago
Please help I’m stuck on this question !!
Ipatiy [6.2K]

Answer:

mode: 17

Step-by-step explanation:

mode is the number that appears the most in a set of data.So the answer is 17

8 0
3 years ago
Please help I don't knew this
schepotkina [342]
The answer to your question is b
7 0
3 years ago
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