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3 years ago

Solve the following equation for z. 3yz+z=-2

Mathematics

1 answer:

vodomira [7]3 years ago

5 0

Answer:

z=-2/3y+1

Step-by-step explanation:

Let's solve for z.

3yz+z=−2

Step 1: Factor out variable z.

z(3y+1)=−2

Step 2: Divide both sides by 3y+1.

z(3y+1)

3y+1

−2

3y+1

−2

3y+1

Answer:

−2

3y+1

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3 years ago

A research group needs to determine a 90% confidence interval for the mean repair cost for all car insurance small claims. From

lutik1710 [3]

Answer:

a) $z = 1.645$

b) The should sample at least 293 small claims.

Step-by-step explanation:

We have that to find our $\alpha$ level, that is the subtraction of 1 by the confidence interval divided by 2. So:

$\alpha = \frac{1-0.9}{2} = 0.05$

Now, we have to find z in the Ztable as such z has a pvalue of $1-\alpha$ .

So it is z with a pvalue of $1-0.05 = 0.95$ , so $z = 1.645$ , which means that the answer of question a is z = 1.645.

Now, find the margin of error M as such

$M = z*\frac{\sigma}{\sqrt{n}}$

In which $\sigma$ is the standard deviation of the population and n is the size of the sample.

(b) If the group wants their estimate to have a maximum error of $12, how many small claims should they sample?

They should sample at least n small claims, in which n is found when

$M = 12, \sigma = 124.88$ . So

$M = z*\frac{\sigma}{\sqrt{n}}$

$12 = 1.645*\frac{124.88}{\sqrt{n}}$

$12\sqrt{n} = 205.43$

$\sqrt{n} = \frac{205.43}{12}$

$\sqrt{n} = 17.12$

$\sqrt{n}^{2} = (17.12)^{2}$

$n = 293$

The should sample at least 293 small claims.

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2 years ago

Two faulty machines, M1 and M2, are repeatedly run synchronously in parallel (i.e., both machines execute one run, then both exe

leonid [27]

The event that either M1 or M2 fails has probability

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by the addition rule. Failure events are independent, so

$P(M_1\text{ and }M_2\text{ both fail})=P(M_1\text{ fails})P(M_2\text{ fails})$

so that

$P(M_1\text{ fails or }M_2\text{ fails})=p_1+p_2-p_1p_2$

Denote this probability by $p$ . Then $X$ follows a geometric distribution with this parameter $p$ and has density

$P(X=x)=\begin{cases}(1-p)^{x-1}p&\text{for }x\ge1\\0&\text{otherwise}\end{cases}$

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3 years ago

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kogti [31]

Answer:

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3 years ago

The square of a number is added to 6

NikAS [45]

I think the answer is x^2+6

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2 years ago