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madam [21]
3 years ago
12

Can anyone help me with #3 on this please

Mathematics
1 answer:
spayn [35]3 years ago
7 0

Answer:

So I can't actually do this at the moment but I'll try to explain what to do

first find the area of the rectangle (12x16)

then, the confusing part, pretend the semicircle is a full circle and find the area and divide by 2

add the two up and put cm^{2} and that should be it

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Svetllana [295]

I really hate these algebra problems pretending to be geometry.  

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4n - 2 = 2n + 32

2n = 34

n = 17

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3 0
3 years ago
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Write an equation in slope-intercept form for the line with slope -2/5 and y-intercept 6 .
lana66690 [7]

y=(-2/5)x + 6

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y-6= (-2/5)x or y=(-2/5)x + 6

5 0
2 years ago
A hot air balloon holds 1,592 cubic meters of helium. The density of helium is 0.1785 kilograms per cubic
yuradex [85]

Answer: 285.2 kg

Step-by-step explanation:

Given

The volume of helium in the balloon is V=1592\ m^3

The density of the helium is \rho =0.1785\ kg/m^3

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\Rightarrow M=\rho \cdot V\\\Rightarrow M=0.1785\times 1592\\\Rightarrow M=285.2\ kg

Thus, the mass of gas is 285.2 kg

3 0
2 years ago
A line passes the points (1,7) and (0,3)what is the equation in the slope intercept form ​
Katen [24]

Answer:

y = 4x+ 3

Step-by-step explanation:

3 0
3 years ago
Use the following matrices, A, B, C and D to perform each operation.
Vinvika [58]

Step-by-step explanation:

A=\left[\begin{array}{ccc}3&1\\5&7\end{array}\right]

B=\left[\begin{array}{ccc}4&1\\6&0\end{array}\right]

C=\left[\begin{array}{ccc}-2&3&1\\-1&0&4\end{array}\right]

D=\left[\begin{array}{ccc}-2&3&4\\0&-2&1\\3&4&-1\end{array}\right]

1.\\A+B=\left[\begin{array}{ccc}3&1\\5&7\end{array}\right]+\left[\begin{array}{ccc}4&1\\6&0\end{array}\right]=\left[\begin{array}{ccc}3+4&1+1\\5+6&7+0\end{array}\right]=\left[\begin{array}{ccc}7&2\\11&7\end{array}\right]

2.\\B-A=\left[\begin{array}{ccc}4&1\\6&0\end{array}\right]-\left[\begin{array}{ccc}3&1\\5&7\end{array}\right]=\left[\begin{array}{ccc}4-3&1-1\\6-5&0-7\end{array}\right]=\left[\begin{array}{ccc}1&0\\1&-7\end{array}\right]

3.\\3C=3\left[\begin{array}{ccc}-2&3&1\\-1&0&4\end{array}\right]=\left[\begin{array}{ccc}(3)(-2)&(3)(3)&(3)(1)\\(3)(-1)&(3)(0)&(3)(4)\end{array}\right]=\left[\begin{array}{ccc}-6&9&3\\-3&0&12\end{array}\right]

4.\\C\cdot D=\left[\begin{array}{ccc}-2&3&1\\-1&0&4\end{array}\right]\cdot\left[\begin{array}{ccc}-2&3&4\\0&-2&1\\3&4&-1\end{array}\right]\\\\=\left[\begin{array}{ccc}(-2)(-2)+(3)(0)+(1)(3)&(-2)(3)+(3)(-2)+(1)(4)&(-2)(4)+(3)(1)+(1)(-1)\\(-1)(-2)+(0)(0)+(4)(3)&(-1)(3)+(0)(-2)+(4)(4)&(-1)(4)+(0)(1)+(4)(-1)\end{array}\right]\\=\left[\begin{array}{ccc}7&-8&-6\\14&13&-8\end{array}\right]

5.\\2D+3C\\\text{This operation can't be performed because the matrices}\\\text{ are of different dimensions.}

6 0
3 years ago
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