Answer:
Explanation:
The main importance of graphics and images in program development is user experience. These graphics, color schemes, clarity, images etc. all come together to create a user interface that individuals will be able to easily navigate and use with extreme ease in order to benefit from what the program is intended to do. An interface of a class of objects allows every button and object in the program to grab and share functionality in order for the entire program to run smoothly.
Answer:
For maximum interoperability, NFSv4 is recommended.
Explanation:
When setting up a network of mostly windows machines, it is better to use NFSv4 because it includes performance improvements, mandates strong security, and a stateful protocol.
#include <iostream>
#include <vector>
std::vector<int> v;
int main(int argc, char* argv[]) {
while(1) {
int temp;
std::cout << "\nEnter a number: ";std::cin>>temp;
if(temp<0) {
std::cout << "\nEven number(s) is/are:\n---------------------\n";
for(int i=0;i<v.size();i++) {
if(v.at(i)%2==0) std::cout << v[i] << " ";
else continue;
}
std::cout << std::endl;
break;
}else {
v.push_back(temp);
}
}
return 0;
}
The correct answer to this question is a certificate of deposit.
A certificate of deposit is an interest bearing account that pays a higher rate of interest than a savings account or interest bearing checking account because you are committing to leave it in the bank for a specified period of time. The CD could be for serveral months, or extend out to multiple years. Normally the interest rate will increase as the length of time increases.
Answer:
Total Memory= 4 KB = 4096 bytes = 32768 bits
Explanation:
<em><u>1. Data lines are 8 From D0 to D7</u></em>
so
Total memory at single address locations is 8 bits.
<em><u>2. Address lines are 12 (A0 to A11)</u></em>
There are 12 address lines but 3 out 12 are for selction of chip or memory bank.
so only 9 pins are there to address the locations on one chip.
Total No. of address locations on single chip = 2^9 = 512 locations
as 1 location is 1 byte so total memory of single chip is 512 bytes.
<u><em>3. Total Memory Bank </em></u>
There are total 3 selection pins for memory bank.
so
Total chips = 2^3 = 8.
<em><u>4. Total Memory </u></em>
Total size of 1 chip = 512 bytes
Total size of 8 chip = 8x512 bytes = 4096 bytes = 4096/1024 kb = 4 kb
<em>So total memory of system is 4 Kb = 4096 bytes = 32768 bits</em>
