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galben [10]
3 years ago
14

____ Is the amount of money owed in addition to the original amount

Mathematics
1 answer:
abruzzese [7]3 years ago
8 0

Answer:

APR INTEREST

THANKS ME LATUR

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PLEASE HELP WILL GIVE BRAINLIEST URGENTTT
alisha [4.7K]

Answer:In geometry, the parallel postulate, also called Euclid's fifth postulate because it is the fifth postulate in Euclid's Elements, is a distinctive axiom in Euclidean geometry. It states that, in two-dimensional geometry

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3 years ago
Three times a number added to half<br> a second <br> number
Licemer1 [7]

Answer:

3x + 1/2x

Step-by-step explanation:

Just replace "a number" with x

"Three times x added to half x"

5 0
3 years ago
In a parallel circuit, the supply voltage is 120 V, 60 Hz. The resistance is 30 Ω and the inductive reactance is 40 Ω. What is t
kvasek [131]

Given : supply voltage = 120V;60 Hz

Inductive Reactance (X_{L}) = 40 Ω

The inductive reactance is given by the formula, X_{L}=Lw, where L is inductance and w is given by formula, w = 2\pi(frequency)

Apply this, we can say that, L = \frac{X_{L}}{2\pi (frequency)}  = \frac{40}{2(3.14)(60)} = 0.106157 H = 106.157 mH

8 0
3 years ago
2 fifth= Ten blank help
Paha777 [63]
2/5 = x/10

2/5 x 2 = 4/10

x= 4

2/5 = 4/10
6 0
3 years ago
A mass weighing 3 lb stretches a spring 3 in. If the mass is pushed upward, contracting the spring a distance of 1 in and then s
Bas_tet [7]

Answer:

Step-by-step explanation:

m=\frac{3}{32}\\ \gamma =0\text{ damping constant.}\\ k=\frac{3}{\frac{1}{4}}=12\\ F(t)=0\\ \text{so equation of motion is }\\ mu''+\gamma u'+ku=F(t)\\ \frac{3u''}{32}+12u=0\\ u''+128u=0\\ \text{and initial conditions are}\\ u(0)=-\frac{1}{12}\\ u'(0)=2\\ u''+128u=0\\ \text{characterstic equation is}\\ r^2+128=0\\ \text{roots are }\\ r=\pm 8\sqrt{2}i\\ \text{therefore general solution is}\\ u(t)=A\cos8\sqrt{2}t+Bsin8\sqrt{2}t\\ \text{using initial conditions we get}\\ A=-\frac{1}{12}\\ B=\frac{\sqrt{2}}{8}\\ \text{therefore solution is }\\ u(t)=-\frac{1}{12}\cos8\sqrt{2}t+\frac{\sqrt{2}}{8}\sin8\sqrt{2}t\\&#10;{hence}\\R=\sqrt{\frac{11}{288}}\\\\\sigma=\pi - \tan^{-1}\frac{1}{\sqrt{2}}\\\\\omega_0=8\sqrt{2}\\T=\frac{4}{4\sqrt{2}}

3 0
3 years ago
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