Let C = cost to rent each chairLet T = cost to rent each table
4C + 8T = 73
2C + 3T = 28
Multiply the 2nd equation by (-2) and then add the equations together
4C + 8T = 73
-4C - 6T = -56
2T = 17T = 17/2 = 8.5
Plug this in to the 1st equation to solve for C
4C + 8(17/2) = 73
4C + 68 = 73
4C = 5C = 5/4 = 1.25
So the cost to rent each chair is $1.25 and the cost to rent each table is $8.50
Answer:
Ti = 5
AT = 6
Kt = 10
Ai = 11
ke = 19
ae = 15
Step-by-step explanation:
6 is in the ten millions place. The number next to 6 is 1, which is less than 5, so you round down. The nearest 10 million is 60,000,000.
D. (xy2 + 3z14)(x2y4 – 3xy2z14 + 9z28