Y = x² + 7x - 4
y = -x - 4
x² + 7x - 4 = -x - 4
+ x + x
x² + 8x - 4 = -4
+ 4 + 4
x² + 8x = 0
x(x) + x(8) = 0
x(x + 8) = 0
x = 0 or x + 8 = 0
- 8 - 8
x = -8
y = -x - 4
y = -0 - 4
y = 0 - 4
y = -4
(x, y) = (0, -4)
or
y = -x - 4
y = -(-8) - 4
y = 8 - 4
y = 4
(x, y) = (-8, 4)
The solutions are (0, -4) and (8, -4).
Answer:
y = x² - 10x + 41
Step-by-step explanation:
The standard form of a quadratic is ax² + bx + c : a ≠ 0
Given
y = (x - 5)² + 16 ← expand (x - 5)²
= x² - 10x + 25 + 16
= x² - 10x + 41 ← in standard form
(b^2+5)(−b^2+7)
Use the FOIL METHOD to expand.
-b^4 + 7b^2 - 5b^2 + 35
-b^4 + 2b^2 + 35
Did you follow?
Answer:
all I know is how to get y but y=122
Step-by-step explanation:
y=3(40)+2
y=120+2
y=122
sorry but I dont know what to do for x
It can be made through straight line or curved lines.
