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Paladinen [302]

3 years ago

13

My neighbour has lived all over the world. I asked how old are you? He said " I lived 1/4 of my life in China, 1/6 of my life in

Vietnam, 1/2 of my life in Cambodia and 22 years in Australia.
How old is he???

1 answer:

drek231 [11]3 years ago

6 0

$\frac{1}{4}x+\frac{1}{6}x+\frac{1}{2}x+22=x|\cdot12\\
3x+2x+6x+264=12x\\
x=264

$

I guess there's a mistake in the question.

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For which of the following is x = -5 a solution? Select all that apply.

ser-zykov [4K]

Answer:

b. -x^2 + 50 = 25

c. |2x| = 10

d. x < 0

e. 2x < 10

Step-by-step explanation:

x = -5

-(-5)² + 50

-25 + 50 = 25

|2(-5)| = |-10| = 10

-5 < 0

2(-5) = -10 < 10

8 0

2 years ago

I have 18 ones 15 hundreds 15 tens 8 thousands and 11 hundred thousands. What number am I?

levacccp [35]

The answer is 1,109,668 .
here is why:
18+ 1,500 is 1,518
1,518 + 150 is 1,668.
1,668+ 8,000 is 9,668
9,668 + 11,00,000 is 1,109,668
18 ones is 18. 15 hundreds is 1,500. 15 tens is 150. 8 thousands is 8,000. 11 hundred thousands is 1,100,000.

4 0

3 years ago

Read 2 more answers

G find the area of the surface over the given region. use a computer algebra system to verify your results. the sphere r(u,v) =

Svetach [21]

Presumably you should be doing this using calculus methods, namely computing the surface integral along $\mathbf r(u,v)$ .

But since $\mathbf r(u,v)$ describes a sphere, we can simply recall that the surface area of a sphere of radius $a$ is $4\pi a^2$ .

In calculus terms, we would first find an expression for the surface element, which is given by

$\displaystyle\iint_S\mathrm dS=\iint_S\left\|\frac{\partial\mathbf r}{\partial u}\times\frac{\partial\mathbf r}{\partial v}\right\|\,\mathrm du\,\mathrm dv$

$\dfrac{\partial\mathbf r}{\partial u}=a\cos u\cos v\,\mathbf i+a\cos u\sin v\,\mathbf j-a\sin u\,\mathbf k$
$\dfrac{\partial\mathbf r}{\partial v}=-a\sin u\sin v\,\mathbf i+a\sin u\cos v\,\mathbf j$
$\implies\dfrac{\partial\mathbf r}{\partial u}\times\dfrac{\partial\mathbf r}{\partial v}=a^2\sin^2u\cos v\,\mathbf i+a^2\sin^2u\sin v\,\mathbf j+a^2\sin u\cos u\,\mathbf k$
$\implies\left\|\dfrac{\partial\mathbf r}{\partial u}\times\dfrac{\partial\mathbf r}{\partial v}\right\|=a^2\sin u$

So the area of the surface is

$\displaystyle\iint_S\mathrm dS=\int_{u=0}^{u=\pi}\int_{v=0}^{v=2\pi}a^2\sin u\,\mathrm dv\,\mathrm du=2\pi a^2\int_{u=0}^{u=\pi}\sin u$
$=-2\pi a^2(\cos\pi-\cos 0)$
$=-2\pi a^2(-1-1)$
$=4\pi a^2$

as expected.

6 0

3 years ago

ANSWER NEEDED QUICK!<br><br> Divide: 5/8 divided by 3/4<br> 1/8<br> 5/6<br> 3/4<br> 1 1/2

Scilla [17]

5/6 I think tahts the answer hope this helps

8 0

3 years ago

2.8 = 2y<br> What does y equal?<br> 1.4<br> 0.5<br> 2.8<br> 0.6

igor_vitrenko [27]

Answer: 1.4

Step-by-step explanation: First, swap the sides of the equation so that the one with the variable can be in front.

So, its 2y=2.8

To solve this, you simply divide both sides of the equation by 2.

2 divided by 2 is 0. That leaves you with the y by itself. Then, 2.8 divided by 2 is 1.4

So, y=1.4

7 0

3 years ago

Read 2 more answers