Answer:
i think your question is missing something??
Step-by-step explanation:
3(4) + 6 = 7 (2(4)-3)
12 + 6 = 7 (8-3)
18 = 7 (5)
18 = 35?
4 cos² x - 3 = 0
4 cos² x = 3
cos² x = 3/4
cos x = ±(√3)/2
Fixing the squared cosine doesn't discriminate among quadrants. There's one in every quadrant
cos x = ± cos(π/6)
Let's do plus first. In general, cos x = cos a has solutions x = ±a + 2πk integer k
cos x = cos(π/6)
x = ±π/6 + 2πk
Minus next.
cos x = -cos(π/6)
cos x = cos(π - π/6)
cos x = cos(5π/6)
x = ±5π/6 + 2πk
We'll write all our solutions as
x = { -5π/6, -π/6, π/6, 5π/6 } + 2πk integer k
7/12 - 3/12 = 1/3
Simplify each fraction if possible.
Same denominator? YES!
7 - 3 = 4
Since they have the same denominator, you just subtract the numerators.
Then simplify 4/12
4/4= 1 12/4= 3
Answer: 1/3
Hope that helps!
Answer:
1. 6
2. 9
3. 9
4. 6
5. 9
6. 6
Step-by-step explanation:
The answers are in the order listed on your assignment page.
Hope this helps :)
Answer:
C
Step-by-step explanation:
B can immediately be eliminated because it has an area of 14.
A and C have an area of 10.
So add the sides.
C:
4 + 4 + 1 + 1 + 2 + 2 + 1 + 3
= 18
A: 3 + 3 + 2 + 2 + 1 + 1 + 1 + 1 =
10 + 4 =
14
