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3 years ago

Which of the following changes is a chemical change? A ice me

Mathematics

1 answer:

Talja [164]3 years ago

5 0

Answer:

Step-by-step explanation:

The question got caught off. Can't read any of the other examples. I can tell you though that ice melting is a physical change, not a chemical change.

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What is the perimeter of a square with side length 13.4 inches

Tamiku [17]

P= perimeter. x= # of inches. 4=number of sides in a square
P= 4x

so, P= 13.4 x 4. Therefore, the perimeter is 53.6 inches.

7 0

3 years ago

The sum of Rayson and his brother’s age is 29. If Rayson is 4 years older than his brother 7 years ago. How old is Rayson and hi

Neko [114]

Answer:

16 years, 13 years

Step-by-step explanation:

Let their ages be x, 29-x

Equation formed:-

(x - 7) + 4 = 29 - x

→ 2x = 29 + 3

→ x = 16 years

Answer: 16 years, 13 years

7 0

3 years ago

Use a transformation to solve the equation. –8c = 56 A. c = –48 B. c = –7 C. c = 7 D. c = 48

Kobotan [32]

-8 times -7 equals 56. there for the answer is -7.

7 0

3 years ago

A number hidden by spilt ink multiplied by 12 equals sixteen thousand, eight hundred and thirty-six. Sixteen thousand, eight hun

Nezavi [6.7K]

Answer:

Step-by-step explanation:

Assume the hidden number is x;

So, if x*12= 16,836

Next, divide both sides by 12 to solve for x;

x= 16,836 / 12

x= 1,403

So the number hidden by spilt ink is 1,403.

Next, to answer the question, divide 16,836 by the hidden number,1403;

16,836 / 1403 = 12

Therefore, it will be equal to 12 which is basically the reverse of the first equation.

6 0

4 years ago

in the life of a car engine, calculatedin miles, is normally distributed, with a mean of 17,000 miels and a standard deviation o

Alinara [238K]

Answer:

the guarantee period should be less than 136010 miles

Step-by-step explanation:

From the given information;

Let consider Y to be the life of a car engine

with a mean μ = 170000

and a standard deviation σ = 16500

The objective is to determine what should be the guarantee period T if the company wants less than 2% of the engines to fail.

i.e

P(Y < T ) < 0.02

For the variable of z ; we have:

$z = \dfrac{x - \mu }{\sigma}$

$z = \dfrac{x - 170000 }{16500}$

Now;

$P(Y < T ) = P( Z < \dfrac{T- 170000}{16500})$

$P( Z < \dfrac{T- 170000}{16500})< 0.02$

From Z table ;

At P(Z < -2.06) ≅ 0.0197 which is close to 0.02

$\dfrac{T- 170000}{16500}$

${T- 170000}$

${T- 170000}< - 33990$

${T}< - 33990+ 170000$

${T}$

Thus; the guarantee period should be less than 136010 miles

4 0

4 years ago