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2 years ago

In the triangle below,

Mathematics

1 answer:

Setler [38]2 years ago

8 0

Answer: 90 degrees

Step-by-step explanation: The other options are not in their neared tens only 90 degrees is.

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Find the equivalent ratio for 32:__=12:24

Igoryamba

32 : 64 = 12 : 24

or

$\displaystyle\\
 \frac{32}{\bf64} = \frac{12}{24}$

6 0

3 years ago

Read 2 more answers

How can I solve this? I need help its for geometry

Scilla [17]

What is the question

4 0

3 years ago

Find the general solution of the differential equation and check the result by differentiation. (Use C for the constant of integ

atroni [7]

Answer: $y=Ce^(^3^t^{^9}^)$

Step-by-step explanation:

Beginning with the first differential equation:

$\frac{dy}{dt} =27t^8y$

This differential equation is denoted as a separable differential equation due to us having the ability to separate the variables. Divide both sides by 'y' to get:

$\frac{1}{y} \frac{dy}{dt} =27t^8$

Multiply both sides by 'dt' to get:

$\frac{1}{y}dy =27t^8dt$

Integrate both sides. Both sides will produce an integration constant, but I will merge them together into a single integration constant on the right side:

$\int\limits {\frac{1}{y} } \, dy=\int\limits {27t^8} \, dt$

$ln(y)=27(\frac{1}{9} t^9)+C$

$ln(y)=3t^9+C$

We want to cancel the natural log in order to isolate our function 'y'. We can do this by using 'e' since it is the inverse of the natural log:

$e^l^n^(^y^)=e^(^3^t^{^9} ^+^C^)$

$y=e^(^3^t^{^9} ^+^C^)$

We can take out the 'C' of the exponential using a rule of exponents. Addition in an exponent can be broken up into a product of their bases:

$y=e^(^3^t^{^9}^)e^C$

The term e^C is just another constant, so with impunity, I can absorb everything into a single constant:

$y=Ce^(^3^t^{^9}^)$

To check the answer by differentiation, you require the chain rule. Differentiating an exponential gives back the exponential, but you must multiply by the derivative of the inside. We get:

$\frac{d}{dx} (y)=\frac{d}{dx}(Ce^(^3^t^{^9}^))$

$\frac{dy}{dx} =(Ce^(^3^t^{^9}^))*\frac{d}{dx}(3t^9)$

$\frac{dy}{dx} =(Ce^(^3^t^{^9}^))*27t^8$

Now check if the derivative equals the right side of the original differential equation:

$(Ce^(^3^t^{^9}^))*27t^8=27t^8*y(t)$

$Ce^(^3^t^{^9}^)*27t^8=27t^8*Ce^(^3^t^{^9}^)$

QED

I unfortunately do not have enough room for your second question. It is the exact same type of differential equation as the one solved above. The only difference is the fractional exponent, which would make the problem slightly more involved. If you ask your second question again on a different problem, I'd be glad to help you solve it.

7 0

2 years ago

109 2/3 divided by 1/2

Alexandra [31]

Answer:

$\large\boxed{219\dfrac{1}{3}}$

Step-by-step explanation:

$109\dfrac{2}{3}:\dfrac{1}{2}\\\\\text{Divide by a fraction is the same operation as multiply by its reciprocal}\\\\109\dfrac{2}{3}:\dfrac{1}{2}=109\dfrac{2}{3}\cdot\dfrac{2}{1}=109\dfrac{2}{3}\cdot2=\left(109+\dfrac{2}{3}\right)\cdot2\\\\\text{use distributive property}\\\\(109)(2)+\left(\dfrac{2}{3}\right)(2)=218+\dfrac{4}{3}=218+1\dfrac{1}{3}=219\dfrac{1}{3}$

3 0

3 years ago

Another geometry question for transition math! Please help me!

Nesterboy [21]

Answer:

The measure of <TRU is 72 deg.

Step-by-step explanation:

<QRU is a right angle, so it measures 90 deg.

Since m<QRT = 18 deg, then m<TRU must be 72 deg since 72 + 18 = 90.

Answer: The measure of <TRU is 72 deg.

6 0

3 years ago