The domain of the function is possible values of independant varaible such that function is defined or have real values.
So the expression

is not defined for x = -6 and for x = 1, as expression becomes undefined for this values of x (Denominator becomes 0).
So answer is,

Option B is correct.
Answer:
increase
Step-by-step explanation:
<u>Question:</u>
Find the number of real number solutions for the equation. x^2 + 5x + 7 = 0
<u>Answer:</u>
The number of real solutions for the equation
is zero
<u>Solution:</u>
For a Quadratic Equation of form :
---- eqn 1
The solution is
Now , the given Quadratic Equation is
---- eqn 2
On comparing Equation (1) and Equation(2), we get
a = 1 , b = 5 and c = 7
In
,
is called the discriminant of the quadratic equation
Its value determines the nature of roots
Now, here are the rules with discriminants:
1) D > 0; there are 2 real solutions in the equation
2) D = 0; there is 1 real solution in the equation
3) D < 0; there are no real solutions in the equation
Now let solve for given equation

Since -3 is less than 0, this means that there are 0 real solutions in this equation.
Answer:
Step-by-step explanation:
x+2
degree is 1

and has two terms so is a binomial
Answer:
23/12 or 1 and 11/12
Step-by-step explanation:
Your first step is that you need to gain a common denomitor. In this scenario, this is 12. To get this, you can either go through the given factors such as 3 having the factors of 6, 9, and 12 and 4 having the factors of 8, and 12.
Another method is the multiply the two given denominators together, but there are certain instances where you shouldn't do that.
Now that you have a common denominator, you need to change the numerators to accomadate the denominators. For 3 to turn into 12, you need to multiply it by 4, thus you have to do the same to the numerator. For 4 to turn into 12, you need to multiply it by 3. This will give you these two new fractions:
8/12 + 15/12
Add the numerators to get 23/12 and then simplify the two numbers to get the mixed number of 1 and 11/12.
Hope this helps!