Answer:
4' x 2' x 1'
Step-by-step explanation:
Collins' cube has a volume of that is the length of any side, x, cubed: Vol = x^3. Since his box has 8^3, we can say that x = 2. <u>[2^3 = 8]</u>
Amil's box has one side that is 2x. That side would be 2*2 = 4 feet. His volume is also 8 ft^3. Amil's box also has a volume of 8 ft^3.
His box dimensions are therefore: (4)(X)(Y) = 8 ft^3 , where X and Y are whole-number dimensions for the other 2 dimensions of his box.
(4)(X)(Y) = 8 ft^3
X*Y = 2
The only combination of whole numbers for which this this would work is 1 and 2.
Amil's box is 4' x 2' x 1' or 8 ft^3
A function is even if, for each x in the domain of f, f (- x) = f (x). The even functions have reflective symmetry through the y-axis. A function is odd if, for each x in the domain of f, f (- x) = - f (x). The odd functions have rotational symmetry of 180º with respect to the origin.
f (x) = (x + 5) ^ 2
f (x) = x ^ 2 + 10x + 25
f (-x) = (-x + 5) ^ 2
f (x) = x ^ 2 - 10x + 25
the function does not comply with the definitions.
The function is NOT even
The function is not odd
answer
neither
The intersection of the gaphs of the two equations are at point (-2, 0) and (3, 5) which are the solutions to the system of equations.
(x+1)2-
=it is meant to be (x+1)2
=2(x) + 2(1)
= 2x +2
I think
