The profit at a factory that makes CD's can be computed using the linear equation p = 2.5d - 1000 where p is the profit and d is
2 answers:
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Answer:
Step-by-step explanation:
ALRIGHT ARE YOU READY FOR EPIC MATH TIME?
because i know i am. so lets get this bread.
WATCH: we have
interesting... that first character is called pi. maybe i should have said, "lets get this pi".
so now lets do some algebra. i am going to work from right to left. lets multiply 6r by 2. that gives us 12r. now we have...
WE ARE MAKING EPIC PROGRESS, AREN'T WE?
lets multiply 12r by 3r. then we have....
notice how i multiplied 12 by 3 and also r by r (which gives 36 and respectively)
so your simplified expression is:
Answer:
With garlic treatment, the mean change in LDL cholesterol is not greater than 0.
Step-by-step explanation:
The dependent <em>t</em>-test (also known as the paired <em>t</em>-test or paired samples <em>t</em>-test) compares the two means associated groups to conclude if there is a statistically significant difference amid these two means.
In this case a paired <em>t</em>-test is used to determine the effectiveness of garlic for lowering cholesterol.
A random sample of 81 subjects were treated with raw garlic. Cholesterol levels were measured before and after the treatment.
The hypothesis for the test can be defined as follows:
<em>H₀</em>: With garlic treatment, the mean change in LDL cholesterol is not greater than 0, i.e. <em>d</em> ≤ 0.
<em>Hₐ</em>: With garlic treatment, the mean change in LDL cholesterol is greater than 0, i.e. <em>d</em> > 0.
The information provided is:
Compute the test statistic value as follows:
The test statistic value is 0.22.
Decision rule:
If the <em>p</em>-value of the test is less than the significance level then the null hypothesis will be rejected and vice-versa.
Compute the <em>p</em>-value of the test as follows:
*Use a <em>t</em>-table.
The <em>p</em>-value of the test is 0.4132.
<em>p-</em>value= 0.4132 > <em>α</em> = 0.01
The null hypothesis was failed to be rejected.
Thus, it can be concluded that with garlic treatment, the mean change in LDL cholesterol is not greater than 0.