Observe the figure given.
Let us complete the given paragraph:
It is given that E is the midpoint of DF. So, DE by the definition of midpoint.
As, midpoint divides the line segment into two equal halves.
Therefore, DE =EF by the segment congruence postulate. DE+EF = DF by the segment addition postulate and so DE+DE = DF by substitution.
Segment Addition Postulate states that given 2 points P and Q, a third point S lies on the line segment PQ if and only if the distances between the points satisfy the equation PS + SQ = PQ.
Simplifying gives 2DE = DF.
Answer:
A
Step-by-step explanation:
To determine which point is a solution, substitute the x- coordinate into the right side of the inequality and compare it's value to the y- coordinate of the point.
A (0, 2)
2x - 1 = 0 - 1 = - 1 → 2 ≥ - 1 ⇒ (0, 2) is a solution
B (4, 1)
2x - 1 = (2 × 4) - 1 = 8 - 1 = 7 → 1 < 7 ⇒ (4, 1) is not a solution
C (0, - 10)
2x - 1 = 0 - 1 = - 1 → - 10 < - 1 ⇒ (0, - 10) is not a solution
D (4, 2)
2x - 1 = (2 × 4) - 1 = 8 - 1 = 7 → 2 < 7 ⇒ (4, 2) is not a solution
Answer:
18
Step-by-step explanation:
Answer:
what probortation?
Step-by-step explanation: