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Vera_Pavlovna [14]
3 years ago
10

Relatable?? yeah uhhh

Mathematics
2 answers:
Ray Of Light [21]3 years ago
7 0

Answer:

OMG- IKR I CAN SOOO RELATE. my brother can annoyed too. lol

evablogger [386]3 years ago
6 0

Answer:O_O

Step-by-step explanation:

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Use the data in the table. Find the median of the data. A) 11 B) 12 C) 13 D) 15
Sphinxa [80]
It would be 12 since the middle numbers are 11 and 13 you take the number in the middle
8 0
3 years ago
A school debate team has 4 girls and 6 boys. A total of 3 of the team members will be chosen to participate in the district deba
mariarad [96]
There are 4+6=10 people in the team.
First calculate in how many ways you can choose 3 people from a group of 10 people, using combination:
(^{10} _3)=\frac{10!}{3!(10-3)!}=\frac{10!}{3! \times 7!}=\frac{7! \times 8 \times 9 \times 10}{6 \times 7!}=\frac{8 \times 9 \times 10}{6}=\frac{720}{6}=120
You can choose 3 people in 120 ways.

You can select 1 girl from a group of 4 girls in 4 ways.
Calculate in how many ways you can choose 2 boys from a group of 6 boys:
(^6 _2)=\frac{6!}{2! (6-2)!}=\frac{6!}{2! \times 4!}=\frac{4! \times 5 \times 6}{2 \times 4!}=\frac{5 \times 6}{2}=\frac{30}{2}=15
You can choose 2 boys in 15 ways.
Using the rule of product, you can calculate that you can choose 1 girl and 2 boys in 4×15=60 ways.

The probability of choosing 1 girl and 2 boys is the number of ways you can choose 1 girl and 2 boys divided by the number of ways you can choose 3 people from the group.
 P=\frac{60}{120}=\frac{1}{2}=50\%

The probability is 1/2, or 50%.
4 0
3 years ago
7. The farmer's den___ big eggs<br>lays or lace ?​
alexandr1967 [171]

Answer:

lays

Step-by-step explanation:

4 0
3 years ago
Choose the equation below that represents the line passing through (1,-4) with a slope or 1/2
olganol [36]

Answer: C. y + 4 = 1/2(x - 1)

Step-by-step explanation:

point slope form is y - y1 = m(x - x1) where m is the slope and (x1, y1) is a point on the line.

6 0
3 years ago
A computer program contains one error. In order to find the error, we split the program into 6 blocks and test two of them, sele
Aleksandr-060686 [28]
There are \dbinom62 ways of selecting two of the six blocks at random. The probability that one of them contains an error is

\dfrac{\dbinom11\dbinom51}{\dbinom62}=\dfrac5{15}=\dfrac13

So X has probability mass function

f_X(x)=\begin{cases}\dfrac13&\text{for }x=1\\\\\dfrac23&\text{for }x=0\end{cases}

These are the only two cases since there is only one error known to exist in the code; any two blocks of code chosen at random must either contain the error or not.

The expected value of finding an error is then

\displaystyle\sum_{x=0}^1xf_X(x)=0\times\dfrac23+1\times\dfrac13=\dfrac13
7 0
3 years ago
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