Answer:
No, because there is just as high of a possibility that the other is biased too.
The simple/ <span>common sense method:
</span>The typical lay out of a quadratic equation is ax^2+bx+c
'c' represents where the line crosses the 'y' axis.
The equation is only translated in the 'y' (upwards/downwards) direction, therefore only the 'c' component of the equation is going to change.
A translation upwards of 10 units means that the line will cross the 'y' axis 10 places higher.
9+10=19,
therefore <u>c=19</u>.
The new equation is: <u>y=x^2+19 </u>
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<span>The most complicated/thorough method:
</span></span>This is useful for when the graph is translated both along the 'y' axis and 'x' axis.
ax^2+bx+c
a=1, b=0, c=9
Find the vertex (the highest of lowest point) of f(x).
Use the -b/2a formula to find the 'x' coordinate of your vertex..
x= -0/2*1, your x coordinate is therefore 0.
substitute your x coordinate into your equation to find your y coordinate..
y= 0^2+0+9
y=9.
Your coordinates of your vertex f(x) are therefore <u>(0,9) </u>
The translation of upward 10 units means that the y coordinate of the vertex will increase by 10. The coordinates of the vertex g(x) are therefore:
<u>(0, 19) </u>
substitute your vertex's y coordinate into f(x)
19=x^2+c
19=0+c
c=19
therefore <u>g(x)=x^2+19</u>
Answer:
D. The small p value and the small effect size suggest that the observed difference between the drug placebo groups are likely to be due to sampling error. This study should be replicated with a larger sample size.
Step-by-step explanation:
The p value is determined for any test before making a conclusion. If the p-value is smaller than critical value then we reject the null hypothesis which means that drug is not effective for the reducing depression. A very small p-value usually lesser than 0.05 indicates strong evidence against the null hypothesis.
The answer: - 2.3 ≥ b ; which does not correspond with any of the answer choices; but most closely corresponds with: "Answer choice: [B]: b > -2.3 ."
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Explanation:
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Assuming we have:
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2.7 is greater than <u><em>or</em></u> equal to "(b + 5)";
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We would write:
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→ 2.7 ≥ b + 5 ;
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→ Subtract "5" from EACH side:
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→ 2.7 − 5 ≥ b + 5 − 5
→ - 2.3 ≥ b ; which does not correspond with any of the answer choices; but most closely corresponds with: "Answer choice: [B]: b > -2.3 ."
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