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Mamont248 [21]
3 years ago
7

Please answer this for me

Mathematics
2 answers:
Pie3 years ago
5 0
3) 2,000.376 inches of water
4) 30.375 for 1 box, 91.125 inches for all three
5) 4,536 feet
6) 24 feet
deff fn [24]3 years ago
4 0
3- multiply 12.6 by 4
4-multiply 4.5 by 4.5 by 3 and once you got your product multiply that by 3
5- multiply 14 by 9 by 6 once you get your product multiply that by 6
6- multiply 4 by 3 by 2 equals 24 feet
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Find the next 3 terms in the sequence 1, 1, 2, 3, 5, 8, . . .
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3 years ago
Find the volume of a pyramid with a square base, where the perimeter of the base is
Kobotan [32]

Answer:

6.8 cubic feet

Step-by-step explanation:

7.3/4=1.825, which is the side length, 1.825*1.825=20.2575 and then ypu divide 20.2575 by 3 because it is a pyramid and that gives you 6.7525

4 0
3 years ago
Did I set this up right?
VashaNatasha [74]

Well if you combine the 3x and the other x it'll be perfect.

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6 0
3 years ago
Read 2 more answers
ΔABC is similar to ΔMNO. The scale factor from ΔMNO to ΔABC is 3∕2 . If the area of ΔMNO is 10 square units, what's the area of
Andrews [41]

Answer:

The area of ΔABC= 6.667 square units

Step-by-step explanation:

ΔABC is similar to ΔMNO.

The scale factor from ΔMNO to ΔABC is 3∕2

the area of ΔMNO is 10 square units,

The area of ΔABC/the area of ΔMNO

= 2/3

The area of ΔABC/10= 2/3

The area of ΔABC= 2/3 * 10

The area of ΔABC= 20/3

The area of ΔABC= 6 2/3

The area of ΔABC= 6.667 square units

6 0
3 years ago
Integrate [0, 1/2] xcos(pi*x).
elena-14-01-66 [18.8K]
To answer your question, this could be the possible answer and i hope you understand and interpret it correctly:
<span>[Integrate [0, 1/2] xcos(pi*x
let u=x so that du=dx
 and v=intgral cos (xpi)dx
        v=(1/pi)sin(pi*x)
 integration by parts
uv-itgral[0,1/2]vdu just plug ins
 (1/pi)sinpi*x]-(1/pi)itgrlsin(pi*x)dx from 0 to 1/2
(1/pi)x sinpi*x - (1/pi)[-(1/pi) cos pi*x] from 0 to 1/2
 =(1/2pi)+(1/pi^2)[cos pi*x/2-cos 0]
=1/2pi - 1/2pi^2
=(pi-2)/2pi^2 ans</span>
3 0
3 years ago
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