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Mamont248 [21]
4 years ago
7

Please answer this for me

Mathematics
2 answers:
Pie4 years ago
5 0
3) 2,000.376 inches of water
4) 30.375 for 1 box, 91.125 inches for all three
5) 4,536 feet
6) 24 feet
deff fn [24]4 years ago
4 0
3- multiply 12.6 by 4
4-multiply 4.5 by 4.5 by 3 and once you got your product multiply that by 3
5- multiply 14 by 9 by 6 once you get your product multiply that by 6
6- multiply 4 by 3 by 2 equals 24 feet
You might be interested in
2x+13=4x-3? Is the correct answer 5 and how did i get the answer because when i checked it i got different answer?
Phoenix [80]

Answer:

x=8, 5 is incorrect.

Step-by-step explanation:

2x8=16+13=29
4x8=32-3=29

4 0
2 years ago
Read 2 more answers
help me please look at picture I sent to know ..! btw show work answer all please ignore the number 5 up top on number 11
rosijanka [135]

Answer:

11) 140/8 = 17.5

12) 38/3 = 12.667

13) 114/9 = 12.667

14) 7/2 = 3.5

15) 14/9 = 1.556

Step-by-step explanation:

To solve each problem you need to multiply the numerator by the whole number:

11) 7*20 = 140

12) 2*19 = 38

13) 6*19 = 114

14) 1*7 = 7

15) 7*2 = 14

Next, you put these numbers back into their corresponding numerators and divide:

11) 140/8 = 17.5     (You can simplify this fraction to 70/4 if needed)

12) 38/3 = 12.667  (This answer is rounded to the thousandths place)

13) 114/9 = 12.667  (This answer is rounded thousandsths place)

14) 7/2 = 3.5

15) 14/9 = 1.556       (This answer is rounded thousandths place)


**These are the improper fractions written as mixed ones** :

11) 17 1/2

12) 12 2/3

13) 12 2/3

14) 3 1/2

15) 1 5/9

I hope this helps!

6 0
4 years ago
Roger can run one mile in 18 minutes. jeff can run one mile in 15 minutes. if jeff gives roger a 1 minute head start, how long w
gladu [14]

Alright, lets get started.

Roger can run one mile in 18 minutes.

Jeff can run one mile in 15 minutes.

Suppose in x minutes, they both will catch up.

Roger runs in 18 minutes = 1 mile

So, Roger will run in 1 minute = \frac{1}{18} miles

So, Roger will run in x minutes = \frac{x}{18} miles

Jeff runs in 15 minues = 1 mile

So, Jeff will run in 1 minute = \frac{1}{15} mile

As Jeff gives roger a 1 minute head start, means Jeff will have x-1 minute time to run

So, Jeff will run in (x-1) minute = \frac{x-1}{15}

As both are cathing up means they both runs same distance, means

\frac{x}{18} =\frac{x-1}{15}

Cross Multiplying

15 x = 18x - 18

3 x = 18

x = 6 minutes

So for calculating distance = speed * time

Distance = \frac{1}{18} *6 = \frac{1}{3} miles

It means it will take 1/3 or 0.33 miles before jeff catches up to roger.   :   Answer

Hope it will help :)



4 0
3 years ago
while on holiday, your family drove 648 km at an average speed of 72 km per hour. how long did it take them to cover the distanc
Anit [1.1K]

Answer:  i think it is (18 km per litre)

6 0
2 years ago
Can someone please help me with these math problems :)
just olya [345]
A)
1) v = 36
2) a = 2

B)
1) c = 22
2) I don’t know

C)
1) P = 2
2) b = 3

I’m not 100% sure these are right but I’m pretty sure :)
7 0
3 years ago
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