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GuDViN [60]
3 years ago
7

The graph of a system of equations is shown below. Which system of equations represents the graph?

Mathematics
1 answer:
exis [7]3 years ago
8 0
I think it might be A. because when you go in y=mx+b form for the line with a y-intercept of -5 you will have a decision between A and C but if you look at the second line it crosses the y-axis at 2. so I’m prettyyyyy sure it’s A but i’m so sorry if i’m not:(
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How many ways can three items be selected from a group of six items? use the letters a, b, c, d, e, and f to identify the items,
vovangra [49]

abc,bca,cba,cab,bac ? then just rotate the others like I did

7 0
3 years ago
an electrition charged $70 for 2 hours of work and 115 for 5hours of work write an equtionto find the cost for y and xk
Westkost [7]

\bf \begin{array}{ccll} \stackrel{x}{hours}&\stackrel{y}{cost}\\ \cline{1-2} 2&70\\ 5&115 \end{array}~\hspace{10em}(\stackrel{x_1}{2}~,~\stackrel{y_1}{70})\qquad (\stackrel{x_2}{5}~,~\stackrel{y_2}{115}) \\\\\\ slope = m\implies \cfrac{\stackrel{rise}{ y_2- y_1}}{\stackrel{run}{ x_2- x_1}}\implies \cfrac{115-70}{5-2}\implies \cfrac{45}{3}\implies 15


\bf \begin{array}{|c|ll} \cline{1-1} \textit{point-slope form}\\ \cline{1-1} \\ y-y_1=m(x-x_1) \\\\ \cline{1-1} \end{array}\implies y-70=15(x-2)\implies y-70=15x-30 \\\\\\ y=15x+40\impliedby \begin{array}{|c|ll} \cline{1-1} slope-intercept~form\\ \cline{1-1} \\ y=\underset{y-intercept}{\stackrel{slope\qquad }{\stackrel{\downarrow }{m}x+\underset{\uparrow }{b}}} \\\\ \cline{1-1} \end{array}


as you already know, a direct proportional variation has a constant of variation "k", y = kx, which in this case that'd be the slope, namely 15.

7 0
3 years ago
How do you graph, identify the domain, range, and asymptotes for y=-2csc2x-1?
faltersainse [42]
The domain is all real numbers except kπ, where k is an integer.
The range is (-∞, -1] ∪ [1, ∞)
Vertical asymtote is kπ, where k is an integer.
4 0
3 years ago
Which function has zeros at x = -2 and x = 5?
riadik2000 [5.3K]

Answer:

<em>f(x)=x²-3x-10</em>

Step-by-step explanation:

\begin{gathered}f(x) = x {}^{2} - 3x - 10 \\ to \: find \: x \: intercept \:o r \: zero \: substitute \: f(x) = 0\: \\ 0 = x {}^{2} - 3x - 10 \\ x {}^{2} - 3x - 10 = 0 \\ x {}^{2} + 2x - 5x - 10 = 0 \\ x(x + 2) - 5x - 10 = 0 \\ x(x + 2) - 5(x + 2) = 0 \\ (x + 2).(x - 5) = 0 \\ x + 2 = 0 \\ x - 5 = 0 \\ x = - 2 \\ x = 5\end{gathered}

f(x)=x

2

−3x−10

tofindxinterceptorzerosubstitutef(x)=0

0=x

2

−3x−10

x

2

−3x−10=0

x

2

+2x−5x−10=0

x(x+2)−5x−10=0

x(x+2)−5(x+2)=0

(x+2).(x−5)=0

x+2=0

x−5=0

x=−2

x=5

therefore the zeros of the equation are x₁=-2,x₂=5

3 0
2 years ago
12 _ (7 - 4) +5 _ 3 = 19
anygoal [31]

The first blank is "division" and the second blank is "multiplying"

12 / (3) = 4

5 x 3 = 15

15 + 4 = 19

7 0
3 years ago
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