Answer:
T-6=X
Step-by-step explanation:
Tracey = T
X = Awnser
If we are subtracting six from Tracey's age, you would subtract six from T
since we don't know Tracey's age, it is represented by T.
Hope this Helps!
You put 4 in the X
1/2(4)+5y-10<0
2+5y-10<0
-8+5y<0
5Y<8
Y<8/5
<span>Find an equation for the line parallel to 2y+4x = 8 and goes through the point (-3,3). Write your answer in the form y=mx+b.</span>
Answer:
<em>Choice: B.</em>
Step-by-step explanation:
<u>Operations With Functions</u>
Given the functions:
![f(x)=\sqrt[3]{12x+1}+4](https://tex.z-dn.net/?f=f%28x%29%3D%5Csqrt%5B3%5D%7B12x%2B1%7D%2B4)
The function (g-f)(x) can be obtained by replacing both functions and subtracting them as follows:
![(g-f)(x)= \log(x-3)+6 - (\sqrt[3]{12x+1}+4)](https://tex.z-dn.net/?f=%28g-f%29%28x%29%3D%20%5Clog%28x-3%29%2B6%20-%20%28%5Csqrt%5B3%5D%7B12x%2B1%7D%2B4%29)
Operating:
![(g-f)(x)= \log(x-3)+6 - \sqrt[3]{12x+1}-4](https://tex.z-dn.net/?f=%28g-f%29%28x%29%3D%20%5Clog%28x-3%29%2B6%20-%20%5Csqrt%5B3%5D%7B12x%2B1%7D-4)
Joining like terms:
![\boxed{(g-f)(x)= \log(x-3) - \sqrt[3]{12x+1}+2}](https://tex.z-dn.net/?f=%5Cboxed%7B%28g-f%29%28x%29%3D%20%5Clog%28x-3%29%20-%20%5Csqrt%5B3%5D%7B12x%2B1%7D%2B2%7D)
Choice: B.
Answer:
To subtract a number from another number, the sign of the number (which is to be subtracted) should be changed and then this number with the changed sign, should be added to the first number
Step-by-step explanation:
(i) Evaluate (+6) – (+2)
= (+6) + (-2) (charging the sign of the number to be subtracted and then adding)
On subtracting smaller number 2 from bigger number 6; we get 6 – 2 = 4
Since, the sign of bigger number is + (positive)
= +4 or 4
Therefore, (+6) – (+2) = 4
(ii) Evaluate (+5) – (-3)
= (+5) + (+3) (charging the sign of the number to be subtracted and then adding)
We know, to add a positive (+ ve) number to a positive (+ ve) number, the numbers should be added and positive sign should be attached to the sum obtained.
= +8
Therefore, (+5) – (-3) = 8
