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sdas [7]
3 years ago
15

I need help I don't understand it

Mathematics
1 answer:
IrinaK [193]3 years ago
3 0
So hmmm check the picture below

the composite figure, is just those rectangles, so, get the area of each, and sum them up, that's the total surface area of it

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The mean number of words per minute (WPM) read by sixth graders is 97 with a standard deviation of 19 WPM. If 75 sixth graders a
andrey2020 [161]

Answer:

0.0174 = 1.74% probability that the sample mean would be greater than 101.63 WPM

Step-by-step explanation:

To solve this question, we need to understand the normal probability distribution and the central limit theorem.

Normal probability distribution

Problems of normally distributed samples are solved using the z-score formula.

In a set with mean \mu and standard deviation \sigma, the zscore of a measure X is given by:

Z = \frac{X - \mu}{\sigma}

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the pvalue, we get the probability that the value of the measure is greater than X.

Central Limit Theorem

The Central Limit Theorem estabilishes that, for a normally distributed random variable X, with mean \mu and standard deviation \sigma, the sampling distribution of the sample means with size n can be approximated to a normal distribution with mean \mu and standard deviation s = \frac{\sigma}{\sqrt{n}};

For a skewed variable, the Central Limit Theorem can also be applied, as long as n is at least 30.

In this problem, we have that:

\mu = 97, \sigma = 19, n = 75, s = \frac{19}{\sqrt{75}} = 2.1939

What is the probability that the sample mean would be greater than 101.63 WPM?

This is 1 subtracted by the pvalue of Z when X = 101.63. So

Z = \frac{X - \mu}{\sigma}

By the Central Limit Theorem

Z = \frac{X - \mu}{s}

Z = \frac{101.63 - 97}{2.1939}

Z = 2.11

Z = 2.11 has a pvalue of 0.9826.

1 - 0.9826 = 0.0174

0.0174 = 1.74% probability that the sample mean would be greater than 101.63 WPM

5 0
3 years ago
From point A and B on level ground, the angles of
gladu [14]

Answer:

Step-by-step explanation:

Call T the top

call G the bottom

T G B is a right triangle

37 at B, 90 at G, thus 53 at BTG

TGA is a right triangle

25 at A, 90 at G, thus 65 at ATG

thus 122 at ABT

law of sines:

sin 25 / BT = sin 12/ 57

so BT = 156 meters (first answer)

now angle ABT = 180 - 12 - 25

= 143

so

sin 143 /AT = sin12/57

AT = 164 meters, second answer

4 0
2 years ago
I will give you BRAINLIEST for the correct answer
masya89 [10]

Answer:

d

Step-by-step explanation:

5 0
3 years ago
Which is equal to 10^12/10^-3
tiny-mole [99]
10^[ 12 - ( - 3 ) ] = 10^( 12 + 3 ) = 10^15 ;
We use the formula
:
3 0
3 years ago
Suppose that the value of a stock varies each day from $13 to $24 with a uniform distribution. (a) Find the probability that the
bogdanovich [222]

Answer:

a. P= 0.6364

b. P = 0.3636

c. Q = $21.25

d. P = 0.5

Step-by-step explanation:

given data

value of a stock varies = $13 to $24

solution

P (stock value is more than $17)

P = \frac{(24-17)}{(24-13)}

P =  \frac{7}{11}

P = 0.6364

and

P (value of the stock is between $17 and $21)

P = \frac{(21-17)}{(24-13)}

P = \frac{4}{11}

P = 0.3636  

and  

Let the upper quartile be Q

\frac{(24 - Q)}{(24 - 13)} = 0.25

\frac{(24 - Q)}{11} = 0.25

(24 - Q) = 2.75

so

Q = $21.25

and

P(X > 20 | X > 16)

P = \frac{(24-20)}{(24-16)}

P = \frac{4}{8}

P = 0.5

3 0
3 years ago
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