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nevsk [136]
3 years ago
5

PLS HELP ASAP with these 4 questions ASAP!!!!!

Mathematics
2 answers:
MrRissso [65]3 years ago
7 0
3. $25. Hope it’s alright
Bingel [31]3 years ago
7 0
Question 2 is 20.2-x=15.2
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F(x)= √x-5. find f-2
rodikova [14]

For this case we have:

Be a function of the form y = f (x)

Where:

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If we want to find f (-2), we substitute x = -2, then:

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So:

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Answer:

f (-2) = \sqrt {7} i


3 0
4 years ago
Describe the transformation of the graph of f into the graph of g as either a horizontal or vertical stretch. f(x)=sqrt(x) and g
SpyIntel [72]
\bf \qquad \qquad \qquad \qquad \textit{function transformations}&#10;\\ \quad \\\\&#10;% left side templates&#10;\begin{array}{llll}&#10;f(x)=&{{  A}}({{  B}}x+{{  C}})+{{  D}}&#10;\\ \quad \\&#10;y=&{{  A}}({{  B}}x+{{  C}})+{{  D}}&#10;\\ \quad \\&#10;f(x)=&{{  A}}\sqrt{{{  B}}x+{{  C}}}+{{  D}}&#10;\\ \quad \\&#10;f(x)=&{{  A}}(\mathbb{R})^{{{  B}}x+{{  C}}}+{{  D}}&#10;\\ \quad \\&#10;f(x)=&{{  A}} sin\left({{ B }}x+{{  C}}  \right)+{{  D}}&#10;\end{array}\\\\&#10;--------------------\\\\

\bf \bullet \textit{ stretches or shrinks horizontally by  } {{  A}}\cdot {{  B}}\\\\&#10;\bullet \textit{ flips it upside-down if }{{  A}}\textit{ is negative}\\&#10;\left. \qquad   \right.  \textit{reflection over the x-axis}&#10;\\\\&#10;\bullet \textit{ flips it sideways if }{{  B}}\textit{ is negative}\\&#10;\left. \qquad   \right.  \textit{reflection over the y-axis}

\bf \bullet \textit{ horizontal shift by }\frac{{{  C}}}{{{  B}}}\\&#10;\left. \qquad  \right. if\ \frac{{{  C}}}{{{  B}}}\textit{ is negative, to the right}\\\\&#10;\left. \qquad  \right.  if\ \frac{{{  C}}}{{{  B}}}\textit{ is positive, to the left}\\\\&#10;\bullet \textit{ vertical shift by }{{  D}}\\&#10;\left. \qquad  \right. if\ {{  D}}\textit{ is negative, downwards}\\\\&#10;\left. \qquad  \right. if\ {{  D}}\textit{ is positive, upwards}\\\\&#10;\bullet \textit{ period of }\frac{2\pi }{{{  B}}}

with that template in mind, let's see    \bf f(x)=\sqrt{x}\qquad &#10;\begin{array}{llll}&#10;g(x)=&\sqrt{0.5x}\\&#10;&\quad \uparrow \\&#10;&\quad  B&#10;\end{array}

so B went form 1 on f(x), down to 0.5 or 1/2 on g(x)
B = 1/2, thus the graph is stretched by twice as much.
8 0
3 years ago
Read 2 more answers
I PROMISE BRAINLIST; 5-STARS; THANKS!! IT'S VERY SIMPLE; BELIEVE ME!!!!!
DochEvi [55]

Answer:

2. B

3. C

4. B

5. D

Step-by-step explanation:

2) The sequence is multiplying by -2 each time. This means that it is geometric.

The next two terms would be:

32*-2=-64\\-64*-2=128\\128*-2=-256

This means that the answer is B

3) The sequence is being multiplied by \frac{1}{3} each time. This means that it is geometric.

The next 3 terms would be:

3*\frac{1}{3} =1 \\\\1*\frac{1}{3} =\frac{1}{3} \\\\\frac{1}{3} *\frac{1}{3} =\frac{1}{9}

I am assuming that the answer is C and that you were unable to type the fractions.

4) We know that the common difference is 1.5, so that is the coefficient of our variable and the starting value is 15. This means that we can write an equation as follows

f(x)=1.5(x-1)+15

Now we can find the first 4 terms

f(1)=15.0\\f(2)=16.5\\f(3)=18.0\\f(4)=19.5

This would mean that the answer is B

5) We know that this is a geometric series, we know the common ratio, and we know the first term. This means we can write the equation as follows

f(x)=4.5(10)^{x-1}

Now we can find the first 4 terms

f(1)=4.5\\f(2)=45\\f(3)=450\\f(4)=4500

Unless you meant that the ratio was \frac{1}{10}, the answer is D, none of the above

7 0
4 years ago
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