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3 years ago

PLS HELP ASAP with these 4 questions ASAP!!!!!

Mathematics

2 answers:

MrRissso [65]3 years ago

7 0

3. $25. Hope it’s alright

Bingel [31]3 years ago

7 0

Question 2 is 20.2-x=15.2

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Name a coordinate point located in quadrant 4

sergiy2304 [10]

A point in quadrant 4 could be (-4,-2)<span />

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3 years ago

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1.6 - 1.3 mathematics

elena-14-01-66 [18.8K]

Answer: 0.3 :) :) :) :)

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3 years ago

F(x)= √x-5. find f-2

rodikova [14]

For this case we have:

Be a function of the form $y = f (x)$

Where:

$f (x) = \sqrt {x-5}$

If we want to find f (-2), we substitute $x = -2$ , then:

$f (-2) = \sqrt {-2-5}\\f (-2) = \sqrt {-7}$

Since we have a negative root, the result will be given by complex numbers. By definition:

$\sqrt {-1} = i$

So:

$f (-2) = \sqrt {7} i$

Answer:

$f (-2) = \sqrt {7} i$

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4 years ago

Describe the transformation of the graph of f into the graph of g as either a horizontal or vertical stretch. f(x)=sqrt(x) and g

SpyIntel [72]

$\bf \qquad \qquad \qquad \qquad \textit{function transformations}
\\ \quad \\\\
% left side templates
\begin{array}{llll}
f(x)=&{{ A}}({{ B}}x+{{ C}})+{{ D}}
\\ \quad \\
y=&{{ A}}({{ B}}x+{{ C}})+{{ D}}
\\ \quad \\
f(x)=&{{ A}}\sqrt{{{ B}}x+{{ C}}}+{{ D}}
\\ \quad \\
f(x)=&{{ A}}(\mathbb{R})^{{{ B}}x+{{ C}}}+{{ D}}
\\ \quad \\
f(x)=&{{ A}} sin\left({{ B }}x+{{ C}} \right)+{{ D}}
\end{array}\\\\
--------------------\\\\$

$\bf \bullet \textit{ stretches or shrinks horizontally by } {{ A}}\cdot {{ B}}\\\\
\bullet \textit{ flips it upside-down if }{{ A}}\textit{ is negative}\\
\left. \qquad \right. \textit{reflection over the x-axis}
\\\\
\bullet \textit{ flips it sideways if }{{ B}}\textit{ is negative}\\
\left. \qquad \right. \textit{reflection over the y-axis}$

$\bf \bullet \textit{ horizontal shift by }\frac{{{ C}}}{{{ B}}}\\
\left. \qquad \right. if\ \frac{{{ C}}}{{{ B}}}\textit{ is negative, to the right}\\\\
\left. \qquad \right. if\ \frac{{{ C}}}{{{ B}}}\textit{ is positive, to the left}\\\\
\bullet \textit{ vertical shift by }{{ D}}\\
\left. \qquad \right. if\ {{ D}}\textit{ is negative, downwards}\\\\
\left. \qquad \right. if\ {{ D}}\textit{ is positive, upwards}\\\\
\bullet \textit{ period of }\frac{2\pi }{{{ B}}}$

with that template in mind, let's see $\bf f(x)=\sqrt{x}\qquad 
\begin{array}{llll}
g(x)=&\sqrt{0.5x}\\
&\quad \uparrow \\
&\quad B
\end{array}$

so B went form 1 on f(x), down to 0.5 or 1/2 on g(x)
B = 1/2, thus the graph is stretched by twice as much.

8 0

3 years ago

Read 2 more answers

I PROMISE BRAINLIST; 5-STARS; THANKS!! IT'S VERY SIMPLE; BELIEVE ME!!!!!

DochEvi [55]

Answer:

2. B

3. C

4. B

5. D

Step-by-step explanation:

2) The sequence is multiplying by -2 each time. This means that it is geometric.

The next two terms would be:

$32*-2=-64\\-64*-2=128\\128*-2=-256$

This means that the answer is B

3) The sequence is being multiplied by $\frac{1}{3}$ each time. This means that it is geometric.

The next 3 terms would be:

$3*\frac{1}{3} =1 \\\\1*\frac{1}{3} =\frac{1}{3} \\\\\frac{1}{3} *\frac{1}{3} =\frac{1}{9}$

I am assuming that the answer is C and that you were unable to type the fractions.

4) We know that the common difference is 1.5, so that is the coefficient of our variable and the starting value is 15. This means that we can write an equation as follows

$f(x)=1.5(x-1)+15$