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3 years ago

HELP!!!!! ASAP!!!!!!

Mathematics

1 answer:

Goshia [24]3 years ago

4 0

I’m sure it’s the last one D

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Your car lease requires a down payment of $1,500 and payments of $450 per month for 36 months. the apr is 6% compounded monthly

Svetach [21]

Monthly interest, i = APR/12 = 0.06/12 = 0.005
Monthly payment, A = $450
Period, n = 36 (months)
Future value of payment
= A((1+i)^n-1)/i
= 450((1.005^36-1)/0.005
= 17701.2472341
Future value of car
F = future value of payment + residual value
= 17701.2472341 + 20000
= 37701.2472341

Present value of car
= downpayment + present value of future payments
= 1500 + F/(1+i)^36
= 1500 + 37701.2472341/(1.005^36)
= 1500 + 31504.86
= 33004.86

8 0

3 years ago

How do you solve: 2(5+r) A :7+r B: 10+2r C: 12r D: 7+2r

maksim [4K]

Answer:

i think it´s b

Step-by-step explanation:

3 0

3 years ago

I need help if you help ill give prize

Minchanka [31]

Answer:

21 oz!

Step-by-step explanation:

21 Tons would be 42,000 pounds, so 21 oz would be the right choice.

8 0

3 years ago

I did a test for math and got a 64. I did a retake with the help of this app and look back at the other test and it just got me

s344n2d4d5 [400]

Answer:

Well, at least you improved. But maybe you should use another source besides brainly for your tests. Sometimes people put the wrong answers just to get points.

I hope you do better next time! Good luck!!

5 0

3 years ago

Help me and i’ll mark you brainliest plus you get 20 points !!!!

Anton [14]

Answer:

Angle bisector

Step-by-step explanation:

Find the measure of the angle COA. By angle addition postulate,

$m\angle COX=m\angle AOX+m\angle COA$

From the diagram,

$m\angle COX=80^{\circ}\\ \\m\angle AOX=40^{\circ},$

then

$80^{\circ}=m\angle COA+40^{\circ}\\ \\m\angle COA=80^{\circ}-40^{\circ}=40^{\circ}$

Find the measure of the angle BOA. By angle addition postulate,

$m\angle BOX=m\angle AOX+m\angle BOA$

From the diagram,

$m\angle BOX=60^{\circ}\\ \\m\angle AOX=40^{\circ},$

then

$60^{\circ}=m\angle BOA+40^{\circ}\\ \\m\angle BOA=60^{\circ}-40^{\circ}=20^{\circ}$

Find the measure of the angle COB. By angle addition postulate,

$m\angle COX=m\angle BOX+m\angle COB$

From the diagram,

$m\angle BOX=60^{\circ}\\ \\m\angle COX=80^{\circ},$

then

$80^{\circ}=m\angle COB+60^{\circ}\\ \\m\angle COB=80^{\circ}-60^{\circ}=20^{\circ}$

This means, the measures of angles COB and BOA are the same and are equal half the measure of angle COA, so angles COB and BOA are congruent. This means, the ray OB is the angle bisector of angle COA

6 0

3 years ago