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scoray [572]
3 years ago
13

Find the volume of the following prism using the formula V = Bh.

Mathematics
2 answers:
Degger [83]3 years ago
7 0
Volume of a Triangle= (b•h•l)/2
(13•10•4)/2
(520)/2
260
V=260
maw [93]3 years ago
6 0

Answer:

v= 260.0

Step-by-step explanation:

Bh length width height

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Find the area of a circle with a circumference of 37.68 units.
Gnom [1K]

Circumference of a circle:

C = 2 pi r

r = C / 2 pi

r = 37.68 / (2 * 3.14)

r = 6

Area of a circle:

A = pi r^2

A = 3.14 * 6^2

A = 113.04

Answer

The area of a circle = 113.04 square units

8 0
4 years ago
Read 2 more answers
Find the area of the quadrilateral with vertices A(0,0) B(2,-3) C(4,0) D(0,4).
muminat

Area of a triangle = ½ * base * height

Area of blue triangle = ½ * 4 * 4

Area of blue triangle = 8

Area of red triangle = ½ * 4 * 3

Area of red triangle = 6

TOTAL AREA = 8 + 6 = 14

6 0
3 years ago
A standard six-sided die is rolled $6$ times. You are told that among the rolls, there was one $1,$ two $2$'s, and three $3$'s.
Alex777 [14]

Answer:

Sequence = 120

Step-by-step explanation:

Given

6 rolls of a die;

Required

Determine the possible sequence of rolls

From the question, we understand that there were three possible outcomes when the die was rolled;

The outcomes are either of the following faces: 1, 2 and 3

Total Number of rolls = 6

Possible number of outcomes = 3

The possible sequence of rolls is then calculated by dividing the factorial of the above parameters as follows;

Sequence = \frac{6!}{3!}

Sequence = \frac{6 * 5 * 4* 3!}{3!}

Sequence = 6 * 5 * 4

Sequence = 120

Hence, there are 120 possible sequence.

7 0
3 years ago
Given the function f(x)= 2|x+6|-4, for what values of x is f(x)=6?
Paraphin [41]

Answer:

x = -1 or x = -11

Step-by-step explanation:

f(x)= 2|x+6|-4

2|x+6|-4 = 6

2|x+6| = 6+4

2|x+6|=10

|x+6| = 10/2

|x+6| = 5

x+6 = ±5

x = ±5 - 6

x = -1 or x = -11

7 0
3 years ago
Please help!!!!!
vampirchik [111]

Answer:

Step-by-step explanation:

Consider the quadratic equation, we have

ax^2+bx+c=0

Dividing the equation by a, we get

x^2+\frac{b}{a}x+\frac{c}{a}=0

Put \frac{c}{a} on the other side,

x^2+\frac{b}{a}x=\frac{-c}{a}

Add (\frac{b}{2a})^2 on both the sides,

x^2+\frac{b}{a}x+(\frac{b}{2a})^2=\frac{-c}{a}+(\frac{b}{2a})^2

completing the square, we have

(x+\frac{b}{2a})^2=\frac{-c}{a}+(\frac{b}{2a})^2

Now, solving for x,

x+\frac{b}{2a}={\pm}\sqrt{\frac{-c}{a}+(\frac{b}{2a})^2}

x=\frac{-b}{2a}{\pm}\sqrt{\frac{-c}{a}+(\frac{b}{2a})^2}

Multiply right side by \frac{2a}{2a},

x=\frac{-b{\pm}\sqrt{b^2-4ac}}{2a}

which is the required quadratic formula.

8 0
4 years ago
Read 2 more answers
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