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inessss [21]
3 years ago
13

USB keys can store terabytes of data. Of the five key factors that contribute to the increasing vulnerability of organizational

information resources, this is an issue related to __________.
Computers and Technology
1 answer:
marissa [1.9K]3 years ago
4 0

Answer:

Increased speed, reduced size and  reduced cost of computers and storage devices.

Explanation:

with massive reduction in the size of storage devices and high processing speed, information theft via such devices have been made easier thereby increasing the vulnerability of an organization's information resources because they have become smaller, faster and cheaper

You might be interested in
1. Print out the string length of s1 2. Loop through characters in s2 with charAt() and display reversed string 3. Compare s2, s
konstantin123 [22]

Answer:

See explaination

Explanation:

public class StringLab9 {

public static void main(String args[]) {

char charArray[] = { 'C', 'O', 'S', 'C', ' ', '3', '3', '1', '7', ' ', 'O', 'O', ' ', 'C', 'l', 'a', 's', 's' };

String s1 = new String("Objected oriented programming language!");

String s2 = "COSC 3317 OO class class";

String s3 = new String(charArray);

// To do 1: print out the string length of s1

System.out.println(s1.length());

// To do 2: loop through characters in s2 with charAt and display reversed

// string

for (int i = s2.length() - 1; i >= 0; --i)

System.out.print(s2.charAt(i));

System.out.println();

// To do 3: compare s2, s3 with compareTo(), print out which string (s2 or s3)

// is

// greater than which string (s2 or s3), or equal, print the result out

if (s2.compareTo(s3) == 0)

System.out.println("They are equal");

else if (s2.compareTo(s3) > 0)

System.out.println("s2 is greater");

else

System.out.println("s3 is greater");

// To do 4: Use the regionMatches to compare s2 and s3 with case sensitivity of

// the first 8 characters.

// and print out the result (match or not) .

if (s2.substring(0, 8).compareTo(s3.substring(0, 8)) == 0)

System.out.println("They matched");

else

System.out.println("They DONT match");

// To do 5: Find the location of the first character 'g' in s1, print it out

int i;

for (i = 0; i < s2.length(); ++i)

if(s2.charAt(i)=='g')

break;

System.out.println("'g' is present at index " + i);

// To do 6: Find the last location of the substring "class" from s2, print it

// out

int index = 0, ans = 0;

String test = s2;

while (index != -1) {

ans = ans + index;

index = test.indexOf("class");

test = test.substring(index + 1, test.length());

}

System.out.println("Last location of class in s2 is: " + (ans + 1));

// To do 7: Extract a substring from index 4 up to, but not including 8 from

// s3, print it out

System.out.println(s3.substring(4, 8));

} // end main

} // end class StringLab9

7 0
3 years ago
Select the correct answer.
Andrei [34K]

Answer: The answer is C

Explanation: When it comes to research papers your topic shouldnt be too broad. Your topic should be broad enough you can find a good amount of information but not too focused that you can't find any information.

7 0
2 years ago
Discuss one simple example of hybrid computer.​
andrezito [222]

Answer:

thermometer , petrol pump

5 0
2 years ago
To remove unwanted parts from an image, select the image and then choose the<br> option
Volgvan

Answer:

You need to make use of the Brush tool for removing the unwanted part of an image.

Explanation:

Yes, it is the brush tool or the lasso tool that you can make use of. and you will find brush tools in all sorts of image processing software may it be the paint or Photoshop. It is common to both the raster-based and vector-based image processing software. And you can easily find it inside the tool section, and then make use of it to remove the unwanted parts from an image.

8 0
3 years ago
Prove the following assertion: For every game tree, the utility obtained by MAX using minimax decisions against a suboptimal MIN
TiliK225 [7]

Answer:

From the given diagram, consider a MIN node whose children are terminal nodes, if MIN plays  

suboptimal. MIN will never be lower than the utility obtained playing against an optimal MIN  

MIN will always select a move having minimax utility greater than or equal to the move that is  

predicted by the minimax that is the MIN-played optimal value.  

Then the MIN node's value is increased to MAX. This is done by induction.  

One can do better than the minimax strategy, if the suboptimal play is predicted by MIN.

If MIN always falls for certain for certain kind of trap and losses, then setting up a trap guarantees a win.

Explanation:

See attached picture also.

5 0
3 years ago
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