The acceleration due to gravity (g) on this planet is 39.44 m/s²
<h3>What is solar system?</h3>
Solar system consists of all the planets and the most importantly the center of the solar system is Sun.
Given is an unknown planet in the outer-reaches of the solar system, a pendulum with a 12 g bob and a string length of 4 m oscillates with a period of 2 seconds.
The time period of the pendulum is
T = 2π √l/g
Squaring both sides, we get
l/g = T² / 4π²
g = 4π²l/ T²
Substitute Time period T = 2s and length l = 4m, we get
g = 4π²x 4/ 2²
g =39.44 m/s²
Thus, the acceleration due to gravity on this planet is 39.44 m/s²
Learn more about solar system.
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Answer:
<u><em>Electric Potential Energy:</em></u>
The energy that is needed to move a charge against an electric firld is called Electric Potential Energy
<u><em>Electric Potential Difference:</em></u>
The amount of work done in carrying a unit charge from one point to an other in an electric field is called Electric Potential Difference.
<u><em>Relation:</em></u>
Relation between Electric potential and electrical potential energy is given by
Here PE represents Electric potential energy
and 
is Electric potential difference
it means electric potential difference is the difference in electric potential energy divided by the charge.
The answer is False because HIV spreads through contact between HIV-infected blood or blood-contaminated body fluids and broken skin, wounds, or mucous membranes. Deep, open-mouth kissing if both partners have sores or bleeding gums and blood from the HIV-positive partner enters the HIV-negative partner's bloodstream.
Ok so it usually includes the evaluation of symptom and disorder severity, patterns of symptoms over time number, frequency, and duration of episodes, and the patient's strengths and weaknesses.
Missing information
Consider a superconducting MRI magnet for which the magnet field decreases from 8.0 T to nearly 0 in 20 s
Answer:
0.152 mV
Explanation:
Change in magnetic field, dB=8-0=8 T
Time interval, dt=20 s
Diameter of ring= 2.2cm hence radius is 1.1 cm equivalent to 0.011
where n is the number of terms and for this question n=1 and A is area which is given by 
hence
and substituting the values
Therefore, induced emf is 0.152 mV
