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Tomtit [17]
3 years ago
13

PLEASE HELP ASAP

Physics
1 answer:
Lerok [7]3 years ago
4 0

Answer:

1. 89.5J

2. 215.25J

3. 0.975J

Explanation:

1. 0.5mv^2 = Ke

2.pe+ke=me

3. mgh = gpe

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Cherise sets identical magnetic carts on two tracks. At the end of each track is a blue magnet that cannot move. Cherise can mov
marusya05 [52]

If you want to maximize your potential energy, you can move the cart in any direction and get the same outcome because the distance it travels in each direction is equal.

The energy that a body possesses in its resting state is called its potential energy. The energy of a moving object is known as its kinetic energy. Stored energy that is conditional on the spatial orientation of the system's components; is also known as potential energy.

When a spring is either squeezed or stretched, the resulting increase in potential energy can be used to do work. Potentially, a steel ball has more energy in the air than it does when it hits the ground.

Here, we can observe that the carts are shifted to the right or left by one space. Consequently, the potential energy will also change in response to the motions.

To see a similar example:

brainly.com/question/20080267

#SPJ4

The right question is:

Cherise sets identical magnetic carts on two tracks. At the end of each track is a blue magnet that cannot move. Cherise can move the carts to one space to the left or one space to the right. Which movement will result in the largest increase in potential energy?

a. Moving the cart on Track 1 one space to the right (→).

b. Moving the cart on Track 2 one space to the left (←).

c. Moving the cart on Track 2 one space to the right (→).

d. All these movements will result in the same change in potential energy because they each move a cart the same distance.

8 0
1 year ago
Please help in physics
Minchanka [31]
As there is no postive or negative assigned so
Initial velocity= -2.8759
Displacement= 0.5at^2+ut
= 0.5(-1.77)(3.33)^2+(-2.8759)(3.33)=-19.4m
4 0
3 years ago
Consider two point charges located on the x axis: one charge, q1= -11.0 nC, is located at x1= -1.675 m; the second charge, q2= 3
Mekhanik [1.2K]

Answer:

Please refer to the figure.

q1 is a negative charge, and q2 and q3 are positive charges. So, the force exerted by q1 on q3 is attractive, and the force exerted by q2 on q3 is repulsive, which means F13 is directed towards left, and F23 is also directed towards left.

F_{13} = \frac{1}{4\pi \epsilon_0}\frac{q_1 q_3}{r_1^2} = \frac{1}{4\pi \epsilon_0}\frac{11\times 10^{-9}\times 47.5\times10^{-9}}{(-1.675 - (-1.18))^2} = 1.92\times 10^{-5}N

F_{23} = \frac{1}{4\pi\epsilon_0}\frac{q_2q_3}{r_2^2} = \frac{1}{4\pi\epsilon_0}\frac{31\times 10^{-9} \times 47.5\times 10^{-9}}{(-1.18 - 0)^2} = 9.5\times 10^{-6}

The net force on q3 is the sum of these two forces:

F_{net} = F_{13} + F_{23} = -1.92\times 10^{-5} + (-19.5\times10^{-6}) = 2.8\times 10^{-5} N

Since both forces are directed towards left, their sign should be negative.

5 0
3 years ago
Band of colors produced when white light is separated into all its colors
Anika [276]
Color spectrum, that rainbow of colors that appears when white light is refracted into a prism to separate all colors of visible light. Basically a rainbow.
5 0
3 years ago
A wall, acted upon by a force of 20 N, does not move. The work done on the wall in this process is
jenyasd209 [6]

Answer:

0 (Zero)

Explanation:

Definition of work done states that ,

Work done on an object is the force applied on that object in the direction of Displacement of the object .

means that ,

W = F.dS (Dot product of Force and displacement)

When the wall is acted upon by the force of 20 N , Wall does not move ,

Thus , displacement of the wall is zero.

So, W = 20×0 = 0.

Thus, Work done on the wall is zero.

8 0
3 years ago
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