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nadya68 [22]
1 year ago
7

Cherise sets identical magnetic carts on two tracks. At the end of each track is a blue magnet that cannot move. Cherise can mov

e the carts one space to the left or one space to the right. Which movement will result in the largest increase in potential energy?.
Physics
1 answer:
marusya05 [52]1 year ago
8 0

If you want to maximize your potential energy, you can move the cart in any direction and get the same outcome because the distance it travels in each direction is equal.

The energy that a body possesses in its resting state is called its potential energy. The energy of a moving object is known as its kinetic energy. Stored energy that is conditional on the spatial orientation of the system's components; is also known as potential energy.

When a spring is either squeezed or stretched, the resulting increase in potential energy can be used to do work. Potentially, a steel ball has more energy in the air than it does when it hits the ground.

Here, we can observe that the carts are shifted to the right or left by one space. Consequently, the potential energy will also change in response to the motions.

To see a similar example:

brainly.com/question/20080267

#SPJ4

The right question is:

Cherise sets identical magnetic carts on two tracks. At the end of each track is a blue magnet that cannot move. Cherise can move the carts to one space to the left or one space to the right. Which movement will result in the largest increase in potential energy?

a. Moving the cart on Track 1 one space to the right (→).

b. Moving the cart on Track 2 one space to the left (←).

c. Moving the cart on Track 2 one space to the right (→).

d. All these movements will result in the same change in potential energy because they each move a cart the same distance.

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A small flashlight bulb provides a resistance of 3 Ω to the 300 mA current that runs through it. Determine the voltage of the ba
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V=IR

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A large truck collides with a small car. True or False: The truck exerted a greater magnitude force on the car than the car exer
Reptile [31]

Answer:

False.

Explanation:

The forces on the car and truck are equal and opposite. The equal forces cause accelerations of the truck and car inversely proportional to their mass. That is, If the Truck A exerts a force FAB on car B, then the car will exert a force FBA on the truck. Therefore,

FBA = −FAB

However, this can be explained by Newton's second law. Let's say the truck has mass M and the car has mass m. If the magnitude of the force that both vehicles experience is F, then the magnitudes of their respective accelerations are:

atruck = F/M

acar = F/m

and combining these we get:

atruck/acar = m/M

So if the mass of the car is a lot less than the mass of the truck, then the acceleration of the truck is much smaller than the acceleration of the car, and if you were to watch the collision, the truck would pretty much seem like it's motion was unaffected, but the car's motion will change quite a bit.

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3 years ago
How do the three types of boundary's work together to keep the Earth at equilibrium?
Maurinko [17]
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8 0
3 years ago
Read 2 more answers
A single-phase electrical load draws 600KVA at 0.6 power factor lagging. a) Find the real and reactive power absorbed by the loa
Whitepunk [10]

Answer:

(a). The reactive power is 799.99 KVAR.

(c). The reactive power of a capacitor to be connected across the load to raise the power factor to 0.95 is 790.05 KVAR.

Explanation:

Given that,

Power factor = 0.6

Power = 600 kVA

(a). We need to calculate the reactive power

Using formula of reactive power

Q=P\tan\phi...(I)

We need to calculate the \phi

Using formula of \phi

\phi=\cos^{-1}(Power\ factor)

Put the value into the formula

\phi=\cos^{-1}(0.6)

\phi=53.13^{\circ}

Put the value of Φ in equation (I)

Q=600\tan(53.13)

Q=799.99\ kVAR

(b). We draw the power triangle

(c). We need to calculate the reactive power of a capacitor to be connected across the load to raise the power factor to 0.95

Using formula of reactive power

Q'=600\tan(0.95)

Q'=9.94\ KVAR

We need to calculate the difference between Q and Q'

Q''=Q-Q'

Put the value into the formula

Q''=799.99-9.94

Q''=790.05\ KVAR

Hence, (a). The reactive power is 799.99 KVAR.

(c). The reactive power of a capacitor to be connected across the load to raise the power factor to 0.95 is 790.05 KVAR.

8 0
3 years ago
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